[英]Using alias column name with CASE in where clause
如何解决此查询? 我收到以下错误:
“ where子句”中的未知列“ count_of_confirmed_rec”
MySQL查询:
SELECT
(SELECT COUNT(a.col_1)FROM table_1 a
JOIN table 2 b ON a.col_id= b.col_id) count_of_confirmed_rec,
c.col_1,
FROM table_3 c
LEFT JOIN table_4 d ON c.col_id = d.col_id
WHERE d.col_1 = 'value'
AND c.col_1 = CASE count_of_confirmed_rec
WHEN 0 THEN 0 ELSE 1 END
首先,您用于计算count_of_confirmed_rec
的子查询与外部查询不相关; 因此,它将为查询的所有返回行提供相同的值。 不确定这是否是您想要的。
其次,您的条件d.col_1 = 'value'
对于左联接也可能放错了位置。
为了在where语句中测试count_of_confirmed_rec
的值,您需要将WHERE语句以外的所有内容放在子查询中,并将条件应用于查询返回的行(未经测试):
select count_of_confirmed_rec, c_col_1 from (
SELECT (SELECT COUNT(a.col_1)FROM table_1 a JOIN table 2 b ON a.col_id= b.col_id) count_of_confirmed_rec, c.col_1 as c_col_1
FROM table_3 c LEFT JOIN table_4 d ON c.col_id = d.col_id
WHERE d.col_1 = 'value'
) SQ
where c_col_1 = CASE count_of_confirmed_rec WHEN 0 THEN 0 ELSE 1 END
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