如何在C ++中加入strcpy

Question

我很困惑，在我的C ++编码中，请帮助我。

#include <conio.h>
#include <string.h>
#include <iostream.h>
main()
{
    char h1[80];
    char h2[80];
    char move[80];
    clrscr();
    cout<<"Character 1 = ";
    gets(h1);
    cout<<"Character 2 = ";
    gets(h2);
    strcpy(move, h1);
    cout<<"Result = "<<move;
    getch();
}

我想要像这样的输出/结果程序

Move  =  h1+h2;

Answer 1

您应该使用strcat连接字符串

strcpy(move, h1);
strcat(move, h2);
cout<<"Result = "<<move;

Answer 2

#include <string>
#include <iostream>
main()
{
    std::string h1;
    std::string h2;
    std::string move;
    std::cout << "Character 1 = ";
    std::cin >> h1;
    std::cout << "Character 2 = ";
    std::cin >> h2;
    move = h1 +h2;
    std::cout << "Result = " << move;
}

Answer 3

#include <conio.h>
#include <string>
#include <iostream>

main()
{
    std::string h1;
    std::string h2;
    std::string move;
    clrscr();
    std::cout << "Character 1 = ";
    std::getline(std::cin, h1);
    std::cout << "Character 2 = ";
    std::getline(std::cin, h2);
    move = h1 + h2;
    std::cout << "Result = " << move;
    getch();
}

Answer 4

使用strcat(move,h2); 添加move和h2变量的内容

strcpy(move, h1);
strcat(move,h2);   // make sure `move` have enough space to concatenate  `h1` and `h2`

Answer 5

首先，它会更好地使用C函数fgets代替C function gets ，因为最后是不安全的，可以覆盖内存..

例如

fgets( h1, 80, stdin );

但是无论如何，最好使用标准的C ++函数getline 。

如果要获取结果为Move = h1 + h2，则应检查Move是否可以容纳字符串串联h1 + h2

所以你可以写

if ( strlen( h1 ) + strlen( h2 ) < 80 )
{
    strcat( strcpy( move, h1 ), h2 );
    cout<<"Result = "<<move;
}