[英]How to set up Google+ Sign-In for server-side apps for a website?
我正在尝试在我的网站上添加带有google +按钮的登录,只是为了检索基本信息。 但是文档对我来说似乎没有任何意义。 ( https://developers.google.com/+/web/signin/server-side-flow ),它似乎已过时且不完整,似乎可以使用各种api库。
谁能更清楚地解释所有这些内容,或告诉我如何进行这项工作以及使用哪个api库等? 完整的示例代码将非常有帮助。
感谢名单
好的,所以我将添加更多细节。 谷歌开发页面以登录按钮为例:
<html>
<head>
<!-- BEGIN Pre-requisites -->
<script src="//ajax.googleapis.com/ajax/libs/jquery/1.8.2/jquery.min.js">
</script>
<script src="https://apis.google.com/js/client:platform.js?onload=start" async defer>
</script>
<!-- END Pre-requisites -->
</head>
<body>
<div id="signinButton">
<span class="g-signin"
data-scope="https://www.googleapis.com/auth/plus.login"
data-clientid="your-client-id"
data-redirecturi="postmessage"
data-accesstype="offline"
data-cookiepolicy="single_host_origin"
data-callback="signInCallback">
</span>
</div>
<div id="result"></div>
<script>
function signInCallback(authResult) {
if (authResult['code']) {
// Hide the sign-in button now that the user is authorized, for example:
$('#signinButton').attr('style', 'display: none');
// Send the code to the server
$.ajax({
type: 'POST',
url: 'plus.php?storeToken',
contentType: 'application/octet-stream; charset=utf-8',
success: function(result) {
// Handle or verify the server response if necessary.
// Prints the list of people that the user has allowed the app to know
// to the console.
console.log(result);
if (result['profile'] && result['people']){
$('#results').html('Hello ' + result['profile']['displayName'] + '. You successfully made a server side call to people.get and people.list');
} else {
$('#results').html('Failed to make a server-side call. Check your configuration and console.');
}
},
processData: false,
data: authResult['code']
});
} else if (authResult['error']) {
// There was an error.
// Possible error codes:
// "access_denied" - User denied access to your app
// "immediate_failed" - Could not automatially log in the user
// console.log('There was an error: ' + authResult['error']);
}
}
</script>
</body>
</html>
但它还提供:
<?php
// Create a state token to prevent request forgery.
// Store it in the session for later validation.
$state = md5(rand());
$app['session']->set('state', $state);
// Set the client ID, token state, and application name in the HTML while
// serving it.
return $app['twig']->render('index.html', array(
'CLIENT_ID' => CLIENT_ID,
'STATE' => $state,
'APPLICATION_NAME' => APPLICATION_NAME
));
// Ensure that this is no request forgery going on, and that the user
// sending us this connect request is the user that was supposed to.
if ($request->get('state') != ($app['session']->get('state'))) {
return new Response('Invalid state parameter', 401);
}
$code = $request->getContent();
$gPlusId = $request->get['gplus_id'];
// Exchange the OAuth 2.0 authorization code for user credentials.
$client->authenticate($code);
$token = json_decode($client->getAccessToken());
// Verify the token
$reqUrl = 'https://www.googleapis.com/oauth2/v1/tokeninfo?access_token=' .
$token->access_token;
$req = new Google_HttpRequest($reqUrl);
$tokenInfo = json_decode(
$client::getIo()->authenticatedRequest($req)->getResponseBody());
// If there was an error in the token info, abort.
if ($tokenInfo->error) {
return new Response($tokenInfo->error, 500);
}
// Make sure the token we got is for the intended user.
if ($tokenInfo->userid != $gPlusId) {
return new Response(
"Token's user ID doesn't match given user ID", 401);
}
// Make sure the token we got is for our app.
if ($tokenInfo->audience != CLIENT_ID) {
return new Response(
"Token's client ID does not match app's.", 401);
}
// Store the token in the session for later use.
$app['session']->set('token', json_encode($token));
$response = 'Succesfully connected with token: ' . print_r($token, true);
?>
但是它并没有说明在哪里放置最后的代码,或者如何引用api库,在哪里放置密码或其他内容。 所以我可以用一些指向正确的方向吗?
好的,所以如果有人遇到麻烦。 我按照这个链接上的教程
我从那里下载了api库,更改了配置文件,并使用了提供的示例,它运行良好。
要使其在本地主机上运行,您必须将您的Authorized JavaScript起源设置为本地主机:#,例如http://localhost:12345
然后让您的浏览器在命令提示符下接受文件夹或登录页面,输入
cd c:/the/path/of/the/downloaded/api/example
然后输入:
php -S localhost:12345
希望对任何人有帮助
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.