![](/img/trans.png)
[英]How to create structure at runtime and convert byte[] pointer to created structure?
[英]how to convert byte pointer to structure
我在将字节指针转换为结构时遇到麻烦(虽然当字节指针作为参数时它隐式工作,但从不强制转换为新对象)
假设我有
[StructLayout(LayoutKind.Sequential)]
public struct x
{
public y;
public zType;
}
这是一个顺序结构,将表示一个byte [],因此当我可以将该byte []分配给此结构并像xy一样使用它时,不必担心偏移量
我的问题是,当我将字节指针byte * ptr = byte []传递给具有此结构作为参数的方法时,它可以工作,但是当我尝试将其正常转换时,它不起作用
//this example works fine
{
byte[] myByteArray = new byte[];
fixed (byte* ptr = myByteArray)
someMethod(ptr)
}
someMethod(x myStruct)
//the next example however doesn't work
{
byte[] myByteArray = new byte[];
fixed (byte* ptr = myByteArray)
x myStruct = (myStruct)ptr
}
我希望我有道理,知道如何投射吗?
重载隐式运算符,如下所示
public unsafe static implicit operator X (byte* ptr)
{
var myX = new x();
x.y = *((type*)(ptr + offset));
return myX;
}
也将byte []运算符重载为类似
public unsafe static implicit operator byte[] (X myX)
{
var myBuffer = new byte[size];
fixed(byte* ptr = myBuffer)
{
*((type*)(ptr + offset)) = myX.y;
}
return myBuffer;
}
现在您几乎可以执行以下操作
byte[] B = new byte[];
fixed(byte* ptr = B)
{
X myX = ptr;
byte[] C = X;
}
我不确定这是否是您想要的,但是是这样的;
using System.Runtime.InteropServices;
namespace ConsoleApplication1
{
class Program
{
[StructLayout(LayoutKind.Sequential)]
public struct x
{
public byte y;
public byte zType;
}
static unsafe void Main(string[] args)
{
var myByteArray = new byte[4];
myByteArray[0] = 1;
myByteArray[1] = 2;
myByteArray[2] = 3;
myByteArray[3] = 4;
fixed (byte* ptr = myByteArray)
{
var myStruct = (x*)ptr;
//myStruct now contain
//myStruct.y == 1
//myStruct.ztype == 2
}
}
}
}
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.