AVAudioPlayer对象声音未播放-迅捷

Question

我在下面创建了AVAudioPlayer的对象类以播放噪音：

class MusicAudio: NSObject, AVAudioPlayerDelegate {

    var bassAudio   : AVAudioPlayer! = AVAudioPlayer()

    override init() {
        super.init()
        let bassAudioPath       = NSBundle.mainBundle().pathForResource("Raw", ofType:"mp3")

        let fileURL = NSURL(fileURLWithPath: bassAudioPath!)
        bassAudio = AVAudioPlayer(contentsOfURL: fileURL, error: nil)
        bassAudio.currentTime = 0
        bassAudio.volume = 1.0
        bassAudio.delegate = self
    }

    func adjustAudioLayerState(volumeOn:Bool, layer:AudioLayerState) {

        if layer == AudioLayerState.Bass {
            self.bassAudio.prepareToPlay()
            self.bassAudio.play()
        }
    }
}

要播放声音，我通过以下方式致电全班：

@IBAction func testSound() {
    var sound:MusicAudio = MusicAudio()
    sound.adjustAudioLayerState(true, layer: AudioLayerState.Bass)

}

但是我没有播放任何音频，有人可以发现我的实现有问题吗？

编辑：rdelmar回答后

var bassAudio   : AVAudioPlayer! = AVAudioPlayer()

class MusicAudio: NSObject, AVAudioPlayerDelegate {

    override init() {
        super.init()
        let bassAudioPath       = NSBundle.mainBundle().pathForResource("Raw", ofType:"mp3")

        let fileURL = NSURL(fileURLWithPath: bassAudioPath!)
        bassAudio = AVAudioPlayer(contentsOfURL: fileURL, error: nil)
        bassAudio.currentTime = 0
        bassAudio.volume = 1.0
        bassAudio.delegate = self
    }

    func adjustAudioLayerState(volumeOn:Bool, layer:AudioLayerState) {

        if layer == AudioLayerState.Bass {
            self.bassAudio.prepareToPlay()
            self.bassAudio.play()
        }
    }
}

Answer 1

您没有听到任何声音，因为MusicAudio类正在被释放。 您需要创建var，sound，属性，而不是局部变量。

class ViewController: UIViewController {

    var sound = MusicAudio()

    @IBAction func testSound() {
        self.sound.adjustAudioLayerState(true, layer: AudioLayerState.Bass)
    }

}