Codeigniter检查用户是否存在于数据库中

Question

我想检查用户是否存在于数据库中。 我的模型中有一个方法如下：我创建一个新user ，从发布的数据中插入id和password ，然后将id传递给函数以检查是否存在具有此id的用户。 但是它给出了以下错误：

---

Severity: Notice Message: Undefined property: Login::$User Filename: controllers/login.php Line Number: 56 Fatal error: Call to a member function user_exists() on a non-object in F:\\xamp\\htdocs\\leoSMS\\application\\controllers\\login.php on line 56 Model name : User

---

用户检查功能

public function user_exists($id){
    $this->db->select('id');
    $this->db->where('id',$id);
    $query = $this ->db->get('user_table');

if ($query->num_rows() > 0)
        return TRUE;
else    
    return FALSE;
}

---

控制器

<?php
class Login extends CI_Controller 
{
    /**  
     * load the magazines
     */
    function __construct(){
        parent::__construct();
        $this->load->library('form_validation');
        $this->load->model('User','National_Holiday','Updated_Holiday');
    }

    public function index() {
        $this->load->view('login'); 
    }

    /** 
     * add a magazine
     */
    public function login()
    {
        $this->form_validation->set_rules(array (
        array(
           'field'  => 'username',
           'label' => 'username',
           'rules' => 'required|is_numeric|max_length[1]|min_length[1]',
           ) ,
        array(
           'field'  => 'password',
           'label' => 'password',
           'rules' => 'required|is_numeric|max_length[1]|min_length[1]',
           ),   
        ));

        $this -> form_validation ->set_error_delimiters(
            '<div class="alert alert-error">','</div>');

        echo $this->input->post('username') . "<br>";
        echo $this->input->post('password'). "<br>";

        $user = new User();
        $user->user_id = $this->input->post('username');
        $user->password = $this->input->post('password');
        echo "<tt><pre>". var_dump($user) . "</tt></pre>";

        if($this->User->user_exists($user->user_id))
            echo "true";
        else {
            echo "false";
        }

        if(!$this->form_validation->run()){
           $this->load->view('login');
        }
       else {
           $this->load->view('national_holiday_screen');
       }
    }
}

Answer 1

尝试使用if($user->user_exists($user->user_id))代替if($this->User->user_exists($user->user_id))

您的语句正在尝试执行未知属性User的方法。 用途可能未定义为Login类的属性。 新语句正在调用User类的对象的方法。 该对象存在是因为您刚刚创建它。

Answer 2

试试这个模型课

function create_member()/** function to create the new user **/
{
    $this->db->where('Username ', $this->input->post('Username '));
    $query = $this->db->get('register');
    if($query->num_rows > 0)
    {
        echo '<div class="alert alert-error"><a class="close" data-dismiss="alert">×</a><strong>';
        echo "Username already taken";  
        echo '</strong></div>';
    }
}