如何从C＃执行PowerShell命令`open-device`？

Question

我正在使用open-device 127.0.0.1连接远程设备。 如何从C＃调用它？ 这段代码：

PowerShell powerShell = PowerShell.Create(); 
PSCommand connect = new PSCommand();
connect.AddCommand("open-device");
powerShell.Commands = connect;
PSOutput = powerShell.Invoke()

导致错误：

System.Management.Automation.CommandNotFoundException ：术语“ open-device未被识别为cmdlet，函数，脚本文件或可运行程序的名称。 检查名称的拼写，或者是否包含路径，请验证路径是否正确，然后重试。 at

  System.Management.Automation.Runspaces.PipelineBase.Invoke(IEnumerable input) at System.Management.Automation.Runspaces.Pipeline.Invoke() at System.Management.Automation.PowerShell.Worker.ConstructPipelineAndDoWork(Runspa‌​ce rs, Boolean performSyncInvoke) 

但是，我可以使用Invoke运行get-service命令。

Answer 1

您需要与第一加载其模块Import-Module cmdlet的当量=>经由完成ImportPSModule()的方法InitialSessionState 。

下面是我的DnsClient模块示例：

using System;
using System.Collections.ObjectModel;
using System.Management.Automation;
using System.Management.Automation.Runspaces;
using System.Text;

namespace PowershellTest1
{
    class Program
    {
        static void Main(string[] args)
        {
            InitialSessionState initial = InitialSessionState.CreateDefault();
            String[] modules = { "DnsClient" };
            initial.ImportPSModule(modules);
            Runspace runspace = RunspaceFactory.CreateRunspace(initial);
            runspace.Open();
            RunspaceInvoke invoker = new RunspaceInvoke(runspace);

            Collection<PSObject> results = invoker.Invoke("Resolve-DnsName 'localhost'");
            runspace.Close();

            // convert the script result into a single string

            StringBuilder stringBuilder = new StringBuilder();
            foreach (PSObject obj in results)
            {
                foreach (PSMemberInfo m in obj.Members)
                {
                    stringBuilder.AppendLine(m.Name + ":");
                    stringBuilder.AppendLine(m.Value.ToString());
                }
            }

            Console.WriteLine(stringBuilder.ToString());
            Console.ReadKey();
        }
    }
}