[英]Defining greater than for a iPhone 6 screen size?
我使用的代码根据设备显示特定的xib文件,目前有3个xib,一个用于iPhone4,一个用于iPhone5,一个用于iPad。
从iOS8 / iPhone 6开始,该应用无法在高于5s的版本上运行,原因是xib不知道要加载什么。
- (IBAction)btnTapForStart:(id)sender {
fromOtherClass=YES;
if([[UIScreen mainScreen]bounds].size.height == 568)
{
PlayMusicViewController *pmvc = [[PlayMusicViewController alloc]initWithNibName:@"XibForIPhone5" bundle:[NSBundle mainBundle]];
[self.navigationController pushViewController:pmvc animated:YES];
}
else
{
PlayMusicViewController *pmvc = [[PlayMusicViewController alloc]init];
[self.navigationController pushViewController:pmvc animated:YES];
}
[appObject.audioPlayer stop];
}
如果我将568的值更改为更高,它将可以工作,但是有没有办法将其组合起来,例如,身高是568或iPhone6尺寸还是iPhone 6加尺寸等?
您可能应该像Maddy所说的那样使用自动布局,但是如果您想拥有适用于特定设备的代码,那么您可能想要实现此实用程序方法。 然后,您可以根据需要创建任意数量的Xib,并将它们定位到特定设备。 例如
if ([[Utilities deviceType] isEqualToString:@"iPhone Retina4"] || [[Utilities deviceType] isEqualToString:@"iPhone Retina35"] ) {
-- do something specific for these phones
}
我将此方法放在实用程序类中。
+ (NSString *)deviceType {
NSString *device = nil;
CGSize screenSize = [[UIScreen mainScreen] bounds].size;
CGFloat deviceScale = [UIScreen mainScreen].scale;
if (UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPhone) {
device = @"iPhone Classic"; // Just in case it doesn't make it through the conditionals
// Classic has a resolution of 480 × 320
if( (screenSize.height == 480 || screenSize.width == 480) && deviceScale == 1.0f ) {
device = @"iPhone Classic";
// Retina has a resolution of 960 × 640
} else if( (screenSize.height == 480 || screenSize.width == 480) && deviceScale == 2.0f ) {
device = @"iPhone Retina35";
// Retina 4" has a resolution of 1136 x 640
} else if (screenSize.height == 568 || screenSize.width == 568 ) {
device = @"iPhone Retina4";
// iPhone 6 has a resolution of 1334 by 750
} else if (screenSize.height == 667 || screenSize.width == 667 ) {
device = @"iPhone 6";
// iPhone 6 Plus has an actual size of 2208 × 1242 and resolution of 1920 by 1080
// Reported size is 736 x 414
} else if (screenSize.height == 736 || screenSize.width == 736 ) {
device = @"iPhone 6 Plus";
}
} else if (UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPad) {
device = @"iPad Classic"; // Just in case it doesn't make it through the conditionals
if(deviceScale == 1.0f) {
device = @"iPad Classic";
} else if (deviceScale == 2.0f) {
device = @"iPad Retina";
}
}
//NSLog(@"The device is %@ scale is %f and the height is %f and width is %f", device, deviceScale, screenSize.height, screenSize.width);
return device;
}
我对枚举做了一些研究,它们很好。 它们使代码更具可读性,但是大多数情况下,它们使编译器可以帮助您键入和捕获错误。 Xcode会自动为您完成deviceType并给您错误:如果尝试使用未定义的值, 请使用未声明的标识符 。 这是重写为枚举的代码。 我为这些值加上LF前缀,但您应该使用适合您项目的任何值。
这是在我的头文件中
// Devices as of Fall 2014
typedef NS_ENUM(NSInteger, LFdeviceType) {
LFDeviceTypePhoneClassic,
LFDeviceTypePhoneRetina3_5,
LFDeviceTypePhoneRetina4,
LFDeviceTypePhone6,
LFDeviceTypePhone6Plus,
LFDeviceTypePadClassic,
LFDeviceTypePadRetina,
};
这是在我的.m文件中。
m+ (NSInteger)deviceType {
CGSize screenSize = [[UIScreen mainScreen] bounds].size;
CGFloat deviceScale = [UIScreen mainScreen].scale;
LFdeviceType device = LFDeviceTypePhoneClassic;
if (UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPhone) {
device = LFDeviceTypePhoneClassic; // Just in case it doesn't make it through the conditionals
// Classic has a resolution of 480 × 320
if( (screenSize.height == 480 || screenSize.width == 480) && deviceScale == 1.0f ) {
device = LFDeviceTypePhoneClassic;
// Retina has a resolution of 960 × 640
} else if( (screenSize.height == 480 || screenSize.width == 480) && deviceScale == 2.0f ) {
device = LFDeviceTypePhoneRetina3_5;
// Retina 4" has a resolution of 1136 x 640
} else if (screenSize.height == 568 || screenSize.width == 568 ) {
device = LFDeviceTypePhoneRetina4;
// iPhone 6 has a resolution of 1334 by 750
} else if (screenSize.height == 667 || screenSize.width == 667 ) {
device = LFDeviceTypePhone6;
// iPhone 6 Plus has an actual size of 2208 × 1242 and resolution of 1920 by 1080
// Reported size is 736 x 414
} else if (screenSize.height == 736 || screenSize.width == 736 ) {
device = LFDeviceTypePhone6Plus;
}
} else if (UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPad) {
device = LFDeviceTypePadClassic; // Just in case it doesn't make it through the conditionals
if(deviceScale == 1.0f) {
device = LFDeviceTypePadClassic;
} else if (deviceScale == 2.0f) {
device = LFDeviceTypePadRetina;
}
}
//NSLog(@"The device is %@ scale is %f and the height is %f and width is %f", device, deviceScale, screenSize.height, screenSize.width);
return device;
}
这样称呼它:
if ( ( [Utilities deviceType] == LFDeviceTypePhoneClassic
|| [Utilities deviceType] == LFDeviceTypePhoneRetina3_5) &&
numberOfFoilsOnScreen > 7 ) {
numberOfFoilsOnScreen = 7;
}
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