[英]SELECT unique values from table with multiple columns containing similar data
我正在尝试从具有3个包含国家代码数据的不同列的表中选择不同国家代码的列表。
例
Raw Desired
+-----------+-----------+-----------+ +-----------+
| country_1 | country_2 | country_3 | | countries |
+-----------+-----------+-----------+ +-----------+
| GBR | GBR | IRL | | ARG |
| DEU | FRA | CHE | | AUS |
| CHN | CHN | IND | | BRA |
| USA | CAN | MEX | | CAN |
| AUS | JAP | KOR | | CHE |
| BRA | ARG | ARG | | CHN |
| NOR | SWE | FIN | | DEU |
| GBR | FRA | GBR | | FIN |
| IRL | IRL | IRL | | FRA |
+-----------+-----------+-----------+ | GBR |
| IND |
| IRL |
| JAP |
| KOR |
| MEX |
| NOR |
| SWE |
| USA |
+-----------+
我到目前为止最接近的是这样的查询:
mysql> SELECT
CONCAT(
(SELECT GROUP_CONCAT(DISTINCT country_1 ORDER BY country_1) FROM tbl),
',',
(SELECT GROUP_CONCAT(DISTINCT country_2 ORDER BY country_2) FROM tbl),
',',
(SELECT GROUP_CONCAT(DISTINCT country_3 ORDER BY country_3) FROM tbl)
) AS countries;
+-------------------------------------------------------------------------------------------------+
| countries |
+-------------------------------------------------------------------------------------------------+
| AUS,BRA,CHN,DEU,GBR,IRL,NOR,USA,ARG,CAN,CHN,FRA,GBR,IRL,JAP,SWE,ARG,CHE,FIN,GBR,IND,IRL,KOR,MEX |
+-------------------------------------------------------------------------------------------------+
但是,正如您所看到的,仍然有重复项,而且我不确定如何将它们分成行。
任何帮助表示赞赏!
我不确定为什么要使用群组连接。 联合可以轻松实现期望的结果,联合会自动删除重复项。
SELECT country1 AS countries FROM tab
UNION
SELECT country2 FROM tab
UNION
SELECT country3 FROM tab
ORDER BY 1;
您得到重复项是因为您仅在每一列中消除了重复项,而不是整体。 您可能想要更多这样的东西:
SELECT GROUP_CONCAT(country)
FROM (
SELECT DISTINCT country1 AS country FROM tbl
UNION
SELECT DISTINCT country2 AS country FROM tbl
UNION
SELECT DISTINCT country3 AS country FROM tbl
)
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