[英]MySQL Get results from multiple tables
我的数据库中有约20张桌子。
我想做的是获得所有分数都超过70的学生的清单
我的查询:
SELECT mysql.*, mssql.*, orecle.* FROM mysql, mssql, orecle;
+----------+------------+------------+------------+----------+------------+------------+------------+----------+-------------+-------------+-------------+
| student | mysqltest1 | mysqltest2 | mysqltest3 | student | mssqltest1 | mssqltest2 | mssqltest3 | student | orecletest1 | orecletest2 | orecletest3 |
+----------+------------+------------+------------+----------+------------+------------+------------+----------+-------------+-------------+-------------+
| student1 | 60 | 70 | 80 | student1 | 80 | 60 | 70 | student1 | 80 | 60 | 50 |
| student2 | 50 | 80 | 90 | student1 | 80 | 60 | 70 | student1 | 80 | 60 | 50 |
| student1 | 60 | 70 | 80 | student2 | 90 | 70 | 50 | student1 | 80 | 60 | 50 |
| student2 | 50 | 80 | 90 | student2 | 90 | 70 | 50 | student1 | 80 | 60 | 50 |
| student1 | 60 | 70 | 80 | student1 | 80 | 60 | 70 | student2 | 90 | 70 | 80 |
| student2 | 50 | 80 | 90 | student1 | 80 | 60 | 70 | student2 | 90 | 70 | 80 |
| student1 | 60 | 70 | 80 | student2 | 90 | 70 | 50 | student2 | 90 | 70 | 80 |
| student2 | 50 | 80 | 90 | student2 | 90 | 70 | 50 | student2 | 90 | 70 | 80 |
+----------+------------+------------+------------+----------+------------+------------+------------+----------+-------------+-------------+-------------+
8 rows in set (0.00 sec)
为什么显示8行而不显示2行?
我想发生的是查询运行时仅输出值大于70的单元格。
我厌倦了几个查询,但是似乎没有任何作用,它们都给了我错误。
SELECT mysql.*, mssql.*, orecle.* FROM mysql, mssql, orecle where ALL > 70;
SELECT mysql.*, mssql.*, orecle.* FROM mysql, mssql, orecle where ALL > '70';
SELECT mysql.*, mssql.*, orecle.* FROM mysql, mssql, orecle where mysql.* OR mssql.* OR orecle.* > 70;
SELECT mysql.*, mssql.*, orecle.* FROM mysql, mssql, orecle where mysql.* OR mssql.* OR orecle.* > '70';
此查询将给我我认为更好的一行
SELECT mysql.*, mssql.*, orecle.* FROM mysql, mssql, orecle where mysql.student='student1' AND mssql.student='student1' AND orecle.student='student1';
+----------+------------+------------+------------+----------+------------+------------+------------+----------+-------------+-------------+-------------+
| student | mysqltest1 | mysqltest2 | mysqltest3 | student | mssqltest1 | mssqltest2 | mssqltest3 | student | orecletest1 | orecletest2 | orecletest3 |
+----------+------------+------------+------------+----------+------------+------------+------------+----------+-------------+-------------+-------------+
| student1 | 60 | 70 | 80 | student1 | 80 | 60 | 70 | student1 | 80 | 60 | 50 |
+----------+------------+------------+------------+----------+------------+------------+------------+----------+-------------+-------------+-------------+
1 row in set (0.01 sec)
但是,约20张桌子可能会变得很复杂; 我也只想看到结果值为70或更高。
要使这种情况发生的最佳查询是什么?
尝试:
SELECT * FROM mysql INNER JOIN
mssql USING (student) INNER JOIN
orecle USING (student);
为了得到两行,而不是2 x 2 x 2 = 8行。
要隐藏分数低于70的单元格,请尝试:
SELECT IF(mysqltest1>70,mysqltest1,null) AS M1,
IF(mysqltest2>70,mysqltest2,null) AS M2,
IF(mysqltest3>70,mysqltest3,null) AS M3,
IF(mssqltest1>70,mssqltest1,null) AS S1,
IF(mssqltest2>70,mssqltest2,null) AS S2,
IF(mssqltest3>70,mssqltest3,null) AS S3,
IF(orecletest1>70,orecletest1,NULL) as O1,
IF(orecletest2>70,orecletest2,NULL) as O2,
IF(orecletest3>70,orecletest3,NULL) as O3 FROM
mysql INNER JOIN
mssql USING (student) INNER JOIN
orecle USING (student);
注意:您在Oracle中有错字。
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