将数组值匹配到JavaScript中的对象属性

Question

我一直在尝试将取自查询字符串的数组值匹配到对象属性并在匹配时返回子对象时遇到问题。

我的数组：

["model1-all", "model2-all", "model3-all"] 

数组可以为空，也可以返回一个，两个或所有值。

我的对象：

[
  {
    "model1-all": [
      {
        "text": "Model1",
        "id": "model1-all",
        "image": "http://example.com/images/model1/front.png",
        "models": [
          {
            "id": "model1-all",
            "text": "All",
            "positiveFeatureCopy": null,
            "negativeFeatureCopy": null,
            "weight": 1000
          },
          {
            "id": "model1-coupe",
            "text": "Coupe",
            "positiveFeatureCopy": null,
            "negativeFeatureCopy": null,
            "weight": 1000
          },
          {
            "id": "model1-convertible",
            "text": "Convertible",
            "positiveFeatureCopy": null,
            "negativeFeatureCopy": null,
            "weight": 1000
          }
        ]
      }
    ],
    "model2-all": [
      {
        "text": "Model2",
        "id": "model2-all",
        "image": "http://example.com/images/model2/front.png",
        "models": [
          {
            "id": "model2-all",
            "text": "All",
            "positiveFeatureCopy": null,
            "negativeFeatureCopy": null,
            "weight": 1000
          },
          {
            "id": "model2-hatchback",
            "text": "Hatchback",
            "positiveFeatureCopy": null,
            "negativeFeatureCopy": null,
            "weight": 1000
          },
          {
            "id": "model2-convertible",
            "text": "Convertible",
            "positiveFeatureCopy": null,
            "negativeFeatureCopy": null,
            "weight": 1000
          },
          {
            "id": "model2-estate",
            "text": "Estate",
            "positiveFeatureCopy": null,
            "negativeFeatureCopy": null,
            "weight": 1000
          }
        ]
      }
    ],
    "model3-all": [
      {
        "text": "Model3",
        "id": "model3-all",
        "image": "http://example.com/images/model3/front.png",
        "models": [
          {
            "id": "model3-all",
            "text": "All",
            "positiveFeatureCopy": null,
            "negativeFeatureCopy": null,
            "weight": 1000
          },
          {
            "id": "model3-saloon",
            "text": "Saloon",
            "positiveFeatureCopy": null,
            "negativeFeatureCopy": null,
            "weight": 1000
          },
          {
            "id": "model3-estate",
            "text": "Estate",
            "positiveFeatureCopy": null,
            "negativeFeatureCopy": null,
            "weight": 1000
          }
        ]
      }
    ]
  }
]

我需要实现的是，当数组中的某个值与对象之一匹配时，例如[{"model1-all" : [... ，我想返回其子对象：

    "models": [
                 {"id":"model1-all", "...":"....", "...", "...":"..."},
                 {"id":"model1-coupe", "...":"....", "...", "...":"..."},
                 {"id":"model1-convertible", "...":"....", "...", "...":"..."}
              ]

我可以使用jQuery或Underscore。

提前致谢

Answer 1

不需要jQuery

var models = [];
var matches = ["model1-all", "model2-all", "model3-all"];

for (var key in data[0]) {
    //No indexOf for IE8 compatibility
    if (matches.indexOf(key) > -1) {
        models.push({
            id: key,
            child: data[0][key]
        });
    }

    //Not using indexOf
    for (var i = 0; i < matches.length; i++) {
        if (matches[i] == key) {
            models.push({
                id: key,
                child: data[0][key]
            });
            break;
        }
    }
}

结果是

models = [
    {
        id: "model1-all",
        child: <object from model1-all>
    },
    ..
]