laravel：将多对多（但只有一个相关项）mysql查询转换为laravel查询

Question

嗨，我在将一直在研究的mysql查询转换为laravel雄辩的查询时遇到麻烦，需要一些帮助。 我有一个预订表，该表链接到具有多对多关系的产品表。 我想取消所有预订，只提取找到的第一个产品，无论与预订相关的产品有多少。 这是我的sql：

SELECT reservations.id,
       reservations.play_date,
       reservations.group_size,
       reservations.status,
       reservations.event_title,
       t4.product_id,
       t4.id AS link_id,
       p1.name,
       CONCAT_WS(" ", customers.first_name, customers.last_name, customers.group_name) AS customerName,
       reservations.event_type
FROM reservations
LEFT JOIN customers ON reservations.customer_id = customers.id
LEFT JOIN
  (SELECT *
   FROM product_reservation AS t3
   GROUP BY t3.reservation_id ) AS t4 ON t4.reservation_id = reservations.id
LEFT JOIN products AS p1 ON t4.product_id = p1.id

我可以将其放置为原始查询，但是会产生一个带有结果的数组-我需要能够创建一个查询对象，以便可以在结果上使用另一个模块。得到这个查询在laravel工作？ 谢谢

Answer 1

是的，您可以使用雄辩的关系。 他们看起来像这样...

class Reservation extends Eloquent
{
    public function products()
    {
        return $this->belongsToMany('Product');
    }
}

class Product
{
    public function reservations()
    {
        return $this->belongsToMany('Reservation');
    }
}

$reservations = Reservation::with(array('products', function($q) {
    $q->take(1);
}))->get();

foreach($reservations as $reservation) {
    echo $reservation->name;
    foreach($reservation->products as $product) {
        echo $product->description;
    }
}