[英]PHP MySQL Join Users Table to Multiple Columns & Rows
对于我正在进行的项目中的项目,我一直有一些问题。
我有3个表,一个用于项目,一个用于客户,一个用于用户。 我正在尝试在Projects表中存储Customers和Users的ID,并在检索时加入它们。
+----+--------------+
| ID | CustomerName |
+----+--------------+
| 1 | Customer 1 |
| 2 | Customer 2 |
| 3 | Customer 3 |
+----+--------------+
+----+-----------+----------+
| ID | FirstName | LastName |
+----+-----------+----------+
| 1 | Bob | Belcher |
| 2 | Stirling | Archer |
| 3 | Bart | Simpson |
| 4 | Peter | Griffin |
| 5 | BoJack | Horseman |
| 6 | Eric | Cartman |
+----+-----------+----------+
+----+---------------+-----------------+-------------+-------------------+-------------------+--------------------+
| ID | ProjectNumber | ProjectCustomer | ProjectLead | ProjectElectrical | ProjectMechanical | ProjectDescription |
+----+---------------+-----------------+-------------+-------------------+-------------------+--------------------+
| 1 | 0001 | 1 | 3 | 4 | 6 | Project 1 |
| 2 | 0002 | 2 | 2 | 5 | 5 | Project 2 |
| 3 | 0003 | 3 | 1 | 6 | 4 | Project 3 |
+----+---------------+-----------------+-------------+-------------------+-------------------+--------------------+
我一整天都在玩Select,这就是我能够搜索到的:
select Projects.ProjectNumber, Customers.CustomerName, CONCAT_WS(' ', Users.FirstName, Users.LastName) AS ProjectLead, Projects.ProjectElectrical, Projects.ProjectMechanical, Projects.ProjectDescription FROM Projects
INNER JOIN Customers ON Projects.ProjectCustomer = Customers.ID
LEFT JOIN Users ON Projects.ProjectLead = Users.ID
这让我成为那里的一部分:
+---------------+--------------+-----------------+-------------------+-------------------+--------------------+
| ProjectNumber | CustomerName | ProjectLead | ProjectElectrical | ProjectMechanical | ProjectDescription |
+---------------+--------------+-----------------+-------------------+-------------------+--------------------+
| 0001 | Customer 1 | Bart Simpson | 4 | 6 | Project 1 |
| 0002 | Customer 2 | Stirling Archer | 5 | 5 | Project 2 |
| 0003 | Customer 3 | Bob Belcher | 6 | 4 | Project 3 |
+---------------+--------------+-----------------+-------------------+-------------------+--------------------+
但对于我的生活,我不能让ProjectElectrical和ProjectMechanical做与ProjectLead相同的事情。 我要么重复ProjectLead,要么得到NULL。
谁能帮助我指出正确的方向? 我是否需要完全重新设计我的查询,还是我在正确的轨道上?
我在SQL Fiddle上搞砸了它
在此先感谢所有回复!
这是来自小提琴的更新查询:
select Projects.ProjectNumber, Customers.CustomerName, CONCAT_WS(' ', Users.FirstName, Users.LastName) AS ProjectLead, CONCAT_WS(' ', u2.FirstName, u2.LastName) AS ProjectElectrical, CONCAT_WS(' ', u3.FirstName, u3.LastName) AS ProjectMechanical, Projects.ProjectDescription FROM Projects
INNER JOIN Customers ON Projects.ProjectCustomer = Customers.ID
LEFT JOIN Users ON Projects.ProjectLead = Users.ID
LEFT JOIN Users AS u2 ON Projects.ProjectElectrical = u2.ID
LEFT JOIN Users AS u3 ON Projects.ProjectMechanical = u3.ID
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.