[英]Taking element from spinner to listview on click and selectable(android)
[英]spinner element to listview on click app crash(android)
因此,我是android / java编程的初学者,并且尝试执行以下操作:单击按钮时,从微调器中选择的项目应该进入列表视图。到目前为止,我这样做是,eclipse不会显示任何错误或警告,但是我尝试启动应用程序时崩溃:
public class MainActivity extends ActionBarActivity {
Button button3;
Button button2;
Button button4;
ListView listView1;
Spinner s1;
String text;
ArrayAdapter<String> adapter;
ArrayList<String> list;
int itemPos;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
button3 = (Button) findViewById(R.id.button3);
button4 = (Button) findViewById(R.id.button4);
button2 = (Button) findViewById(R.id.button2);
s1 = (Spinner) findViewById(R.id.spinner1);
listView1 = (ListView) findViewById(R.id.listView1);
adapter = new ArrayAdapter<String>(this,
android.R.layout.simple_list_item_single_choice, list); //this part here might not be correct
listView1.setAdapter(adapter);
button3.setOnClickListener(new View.OnClickListener() {
public void onClick(View v) {
String text = s1.getSelectedItem().toString();
adapter.add(text);
}});
listView1.setOnItemClickListener(new OnItemClickListener() {
@Override
public void onItemClick(AdapterView<?> parent, View view,
int position, long id) {
itemPos = position;
}
});}}
我不明白为什么它崩溃,如何解决?
谢谢!
宣布,
ArrayList<String> list = new ArrayList<String>();
现在,您不能直接在ArrayAdapter中发送文本,因为我们已经创建了ArrayList。
所以喜欢这样
button3.setOnClickListener(new View.OnClickListener() {
public void onClick(View v) {
String text = s1.getSelectedItem().toString();
list.add(text);
// To notify adapter after that changes in data
adapter.notifyDataSetChanged();
}
});
让我们来解决问题。
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