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[英]How to send data from popup.js to content.js in a Chrome Extension
[英]how to pass localstorage from popup.js to content.js
我想将数据从popup.hmtl的本地存储传递到内容脚本content.js,我使用popup.html接收用户名和密码并将其存储在本地存储中。现在,我想在执行之前将数据传输到内容脚本。
**popup.html**
<!DOCTYPE html>
<html>
<head>
<script type="text/javascript" async src="popup.js"></script>
</head>
<body>
<table>
<tr>
<td>
Username:
<td><input id="u1" type="text" name="uname">
</tr>
<tr>
<td>
Password:
<td><input id="u2" type="password" name="pass">
</tr>
<tr>
<td>
<td>
<input id="clickme" type="button" value="save" />
</tr>
</table>
<div id="result"></div>
<div id="result2"></div>
</body>
</html>
popup.js
document.getElementById('clickme').onclick=myfunction;
var sname = localStorage.getItem("username1");
var spass=localStorage.getItem("password1");
document.getElementById("result").innerHTML = localStorage.getItem("username1");
document.getElementById("result2").innerHTML=localStorage.getItem("password1");
function myfunction(){
// Check browser support
if (typeof(Storage) != "undefined") {
var uname="bhuwan";
var username=document.getElementById("u1").value;
var password=document.getElementById("u2").value;
// Store
localStorage.setItem("username1", username);
localStorage.setItem("password1",password);
// Retrieve
document.getElementById("result").innerHTML = localStorage.getItem("username1");
document.getElementById("result2").innerHTML=localStorage.getItem("password1");
} else {
document.getElementById("result").innerHTML = "Sorry, your browser does not support Web Storage...";
}
}
chrome.runtime.onMessage.addListener(function(request, sender, sendResponse) {
if (request.method == "getLocalStorage")
sendResponse({data: localStorage[request.key]});
else
sendResponse({}); // snub them.
});
content.js
{
var pid="";
var cid="";
chrome.runtime.sendMessage({method: "getLocalStorage",key="username"}, function(response) {
var cid = response.data;
});
chrome.runtime.sendMessage({method: "getLocalStorage"},key="password" function(response) {
var pid = response.data;
});
}
我找到了答案:
将以下代码从popup.js转移到后台.js
chrome.runtime.onMessage.addListener(function(request, sender, sendResponse) {
if (request.method == "getLocalStorage")
sendResponse({data: localStorage[request.key]});
else
sendResponse({}); // snub them.
});
由于popup.js仅在单击图标时处于活动状态,因此无法传递消息。
您正在尝试通过向弹出页面发送消息来检索数据。
问题在于:弹出页面仅在显示时存在。 当它关闭时,它被销毁,您的onMessage
侦听器不存在,并且请求失败。
这正是背景或事件页面的用途-持久事件侦听器。 此外,后台页面与弹出窗口共享localStorage
,因此在那里没有问题。
chrome.storage
, localStorage
有一个更好的替代方法,可用于弹出脚本和内容脚本,而无需任何消息传递: chrome.storage
API 。
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