[英]Why join table is not working in symfony2?
我的Post.php
<?php
// src/Acme/UserBundle/Entity/User.php
namespace Acme\PostBundle\Entity;
use Doctrine\ORM\Mapping as ORM;
use Symfony\Component\Validator\Constraints as Assert;
/**
* @ORM\Entity
* @ORM\Table(name="posts")
*/
class Post
{
/**
* @ORM\Id
* @ORM\Column(type="integer")
* @ORM\GeneratedValue(strategy="AUTO")
*/
protected $id;
/**
*
* @ORM\Column(type="integer")
*/
public $user_id;
/**
* @ORM\ManyToOne(targetEntity="Acme\PostBundle\Entity\User", inversedBy="posts")
* @ORM\JoinColumn(name="id", referencedColumnName="id")
*/
protected $user;
/**
* @ORM\Column(type="string", length=255)
* @Assert\NotBlank(message="Введите текст")
* )
*/
protected $text;
/**
* @ORM\Column(type="string", length=255)
*/
protected $address;
/**
*
* @ORM\Column(type="datetime")
*/
protected $date;
}
和我的User.php:
<?php
// src/Acme/UserBundle/Entity/User.php
namespace Acme\PostBundle\Entity;
use Doctrine\ORM\Mapping as ORM;
use Doctrine\Common\Collections\ArrayCollection;
/**
* @ORM\Entity
* @ORM\Table(name="users")
*/
class User
{
/**
* @ORM\Id
* @ORM\Column(type="integer")
* @ORM\GeneratedValue(strategy="AUTO")
*/
protected $id;
/**
*
* @ORM\Column(type="string")
*/
protected $path;
/**
* @ORM\OneToMany(targetEntity="Acme\PostBundle\Entity\Post", mappedBy="users")
*/
protected $posts;
public function __construct() {
$this->posts = new ArrayCollection();
}
}
我想按表“ posts”中的“ user_id”列创建联接表用户和帖子。 接下来,我使用queryBuilder进行查询:
$repository = $this->getDoctrine()->getManager()->getRepository('AcmePostBundle:Post');
$queryPosts = $repository->createQueryBuilder('p')
->orderBy('p.id', 'DESC')
->getQuery();
return new Response(var_dump($queryPosts->getResult()));
我得到:
object(Acme\PostBundle\Entity\Post)[476]
protected 'id' => int 1
public 'user_id' => int 1
protected 'user' =>
object(Proxies\__CG__\Acme\PostBundle\Entity\User)[475]
public '__initializer__' =>
object(Closure)[469]
...
public '__cloner__' =>
object(Closure)[470]
...
public '__isInitialized__' => boolean false
protected 'id' => int 1
protected 'path' => null
protected 'posts' => null
protected 'text' => string 'Test' (length=4)
protected 'address' => string 'Test' (length=4)
protected 'date' =>
object(DateTime)[477]
public 'date' => string '2014-11-06 14:39:13' (length=19)
public 'timezone_type' => int 3
public 'timezone' => string 'Europe/Kiev' (length=11)
为什么user-> path为null? 如何使此联接在表中
当使用辅助函数(如find()
或findAll()
,Doctrine利用延迟加载方法来按需获取相关实体,但是当您使用查询生成器时,您正在创建显式的查询/结果,这些查询/结果不会被Doctrine的lazy处理-loader。
使用查询生成器时,必须显式加入其他相关实体:
$queryPosts = $this->getDoctrine()->getManager()->createQueryBuilder()
->select('p, u')
->from('AcmePostBundle:Post', 'p')
->leftJoin('p.user','u') // handles the ManyToOne association automatically
->orderBy('p.id', 'DESC')
->getQuery();
请注意,您可以轻松地使用innerJoin
而不是leftJoin
但是如果您有任何具有空关联的潜在Post
项,则可以解决此问题。
您还必须确保您的实体映射正确:
/**
* @ORM\ManyToOne(targetEntity="Acme\PostBundle\Entity\User", inversedBy="posts")
* @ORM\JoinColumn(name="user_id", referencedColumnName="id")
*/
protected $user;
不然原则将尝试匹配id
后的对id
的用户的。 (类似于LEFT JOIN Post ON Post.id = User.id
到达原始查询时的状态)
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.