[英]How Do I Let the C# Compiler Ignore Primitive Types and Numeric String Values for JSON String in Dynamic Data?
当原始类型“ string”和数字字符串值“ 01”,“ 02”用于动态数据时,解析JSON String时出现编译器错误。 我正在使用安装了.Net 4.0的JavaScriptSerializer。 请参阅下面的C#代码段清单:
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Web.Script.Serialization;
using System.Collections;
namespace DynamicJsonParser
{
class Program
{
static void Main(string[] args)
{
const string json = "{\"options\":{\"01\":{\"enabled\":01,\"string\":\"Battery\"},\"02\":{\"enabled\":00,\"string\":\"Steering Sensor\"}}}";
var serializer = new JavaScriptSerializer();
serializer.RegisterConverters(new[] { new DynamicJsonConverter() });
dynamic data = serializer.Deserialize<object>(json);
// Compiling error when I use the primitive types
// and string numerical values for dynamic data:
// "01,02,string" for the JSON String.
// How do I let the compiler know that I am using the
// above primitive types and string numerical values
// for dynamic data instead in the JSON String?
Console.WriteLine(data.options.01.enabled); // Compiler Error.
Console.WriteLine(data.options.01.string); // Compiler Error.
Console.WriteLine(data.options.02.enabled); // Compiler Error.
Console.WriteLine(data.options.02.string); // Compiler Error.
Console.WriteLine("Done!");
}
}
}
这并不是引用反序列化数据的正确方法。 相反,您可以执行以下操作:
const string json = "{\"options\":{\"01\":{\"enabled\":01,\"string\":\"Battery\"},\"02\":{\"enabled\":00,\"string\":\"Steering Sensor\"}}}";
var serializer = new JavaScriptSerializer();
var data = serializer.Deserialize<dynamic>(json);
Console.WriteLine(data["options"]["01"]["enabled"]);
Console.WriteLine(data["options"]["01"]["string"]);
Console.WriteLine(data["options"]["02"]["enabled"]);
Console.WriteLine(data["options"]["02"]["string"]);
您不需要动态的 。 您可以反序列化为Dictionary 。
string json = "{\"options\":{\"01\":{\"enabled\":01,\"string\":\"Battery\"},\"02\":{\"enabled\":00,\"string\":\"Steering Sensor\"}}}";
var serializer = new JavaScriptSerializer();
var root = serializer.Deserialize<Root>(json);
foreach (var item in root.options)
{
Console.WriteLine(item.Key + ": " + item.Value.enabled + "," + item.Value.@string);
}
public class Item
{
public int enabled { get; set; }
public string @string { get; set; }
}
public class Root
{
public Dictionary<string, Item> options { get; set; }
}
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