删除T-SQL中的最后一个数字

Question

如何从tsql的数据和组中删除最后一个数字，
询问

select browser from Table1 group by browser

结果

Chrome11
Chrome28
Chrome30
Chrome31
Chrome32
Chrome33
Firefox12
Firefox22
Firefox30
Firefox32
Firefox33
IE10
IE7
IE8
IE9
IEMobile
IEMobile10
InternetExplorer11
Mozilla
Opera9
Safari
Safari5
Safari6

所需格式

  Chrome
  Firefox
  IE
  Safari
  InternetExplorer
  Mozilla
  IEMobile

注意：我们不禁止客户端使用哪个浏览器

Answer 1

这将为您工作..

select distinct browser from (
select REPLACE (REPLACE(REPLACE(REPLACE(REPLACE(REPLACE(REPLACE(REPLACE(REPLACE(REPLACE 
(browser, '0', ''),'1', ''),'2', ''),'3', ''),'4', ''),'5', ''),
          '6', ''),'7', ''),'8', ''),'9', '') as  browser
 from  TestTable  group by  browser)  temp

Answer 2

您可以使用嵌套的REPLACE（），它最多可以扩展到32个级别：

DECLARE @mystring NVARCHAR(30)

SET @mystring = 'TEST76'

select REPLACE
(REPLACE
(REPLACE
(REPLACE
(REPLACE
(REPLACE
(REPLACE
(REPLACE
(REPLACE
(REPLACE (@mystring, '0', ''),
'1', ''),
'2', ''),
'3', ''),
'4', ''),
'5', ''),
'6', ''),
'7', ''),
'8', ''),
'9', '')

结果：测试

希望这可以帮助。

Answer 3

WITH ExampleCte(Browser) AS (
    SELECT 
        'Chrome11'           UNION ALL SELECT 
        'Chrome28'           UNION ALL SELECT 
        'Chrome30'           UNION ALL SELECT 
        'Chrome31'           UNION ALL SELECT 
        'Chrome32'           UNION ALL SELECT 
        'Chrome33'           UNION ALL SELECT 
        'Firefox12'          UNION ALL SELECT 
        'Firefox22'          UNION ALL SELECT 
        'Firefox30'          UNION ALL SELECT 
        'Firefox32'          UNION ALL SELECT 
        'Firefox33'          UNION ALL SELECT 
        'IE10'               UNION ALL SELECT 
        'IE7'                UNION ALL SELECT 
        'IE8'                UNION ALL SELECT 
        'IE9'                UNION ALL SELECT 
        'IEMobile'           UNION ALL SELECT 
        'IEMobile10'         UNION ALL SELECT 
        'InternetExplorer11' UNION ALL SELECT 
        'Mozilla'            UNION ALL SELECT 
        'Opera9'             UNION ALL SELECT 
        'Safari'             UNION ALL SELECT 
        'Safari5'            UNION ALL SELECT 
        'Safari6'
)
SELECT 
    Browser,
    Left(Browser, Len(Browser) - PatIndex('%[^0-9]%', Reverse(Browser)) + 1) AS BrowserWithoutNumber
FROM 
    ExampleCte

Answer 4

您可以执行以下操作：

测试数据：

DECLARE @tbl TABLE(browser VARCHAR(100))

INSERT INTO @tbl
VALUES
('Chrome11'),('Chrome28'),('Chrome30'),
('Chrome31'),('Chrome32'),('Chrome33'),
('Firefox12'),('Firefox22'),('Firefox30'),
('Firefox32'),('Firefox33'),('IE10'),
('IE7'),('IE8'),('IE9'),('IEMobile'),
('IEMobile10'),('InternetExplorer11'),('Mozilla'),
('Opera9'),('Safari'),('Safari5'),('Safari6')

然后是这样的查询：

;WITH CTE
AS
(
    SELECT
        (
        CASE 
            WHEN PATINDEX('%[0-9.-]%', browser) = 0 
            THEN browser
            ELSE SUBSTRING(browser,0,PATINDEX('%[0-9.-]%', browser)) 
        END
        ) AS browser
    FROM 
        @tbl AS tbl
)
SELECT
    *
FROM
    CTE
GROUP BY
    CTE.browser

这将为您提供如下输出：

Chrome
Firefox
IE
IEMobile
InternetExplorer
Mozilla
Opera
Safari

参考：

• 订阅（Transact-SQL）
• PATINDEX（Transact-SQL）

Answer 5

创建一个函数：

Create Function fnStrFromAlphaNum(@str varchar(100))
returns varchar(100)
as
begin
    if patindex('%[0-9]%',@str)>0
        set @str = SUBSTRING(@str,1,patindex('%[0-9]%',@str)-1)
    return @str
end

在查询中调用此函数：

select distinct fnStrFromAlphaNum(browser)
from table1

Answer 6

您可以这样：

WITH cte AS
   (SELECT rtrim(
              substring(
                 browser,
                 1,
                 PATINDEX('%[0-9]%', browser) -1
              )
           ) as browser
    FROM table)
SELECT cte.browser FROM cte
GROUP BY cte.browser