[英]java json string to arraylist of objects
我有Json String,看起来像这样
String RET=[{"id":"1","name":"koukouvagia","category":"c","lat":"35.52563370000000","lon":"24.05584680000000","address":"Alexi Minoti","phone":"2821027449","counter":"0"},{"id":"2","name":"theatro","category":"c","lat":"35.51392000000000","lon":"24.01979000000000","address":"Plateia Agoras 69","phone":"2821008500","counter":"0"},{"id":"3","name":"mikro kafe","category":"c","lat":"35.51700560000000","lon":"24.02495420000000","address":"Akth Miaouli 6","phone":"2821059321","counter":"0"},{"id":"4","name":"mikro efeteio","category":"c","lat":"35.51033020000000","lon":"24.03102900000000","address":"Plateia Dikastirion","phone":"2821028112","counter":"0"},{"id":"5","name":"Grhgorhs","category":"c","lat":"35.51355300000000","lon":"24.02024900000000","address":"N.Plasthra \u0026 S.Venizelou","phone":"0","counter":"0"}]
并希望将此Json字符串转换为Objects的arraylist并将所有元素放在一个类(Data Object.class)上并打印这些元素。
Type listOfTestObject=new TypeToken<List<DataObject>>(){}.getType();
List<DataObject> list2 = g.fromJson(RET, listOfTestObject);
for(int i = 0; i < list2.size(); i++) {
System.out.println(list2.get(i).getNameF());
}
输出为:
null
null
null
null
null
我创建的类具有该形式
public class DataObject {
String idF;
String nameF;
String categoryF;
String latF;
String lonF;
String addressF;
String phoneF;
String counterF;
public String getIdF() {
return idF;
}
public void setIdF(String idF) {
this.idF = idF;
}
public String getNameF() {
return nameF;
}
public void setNameF(String nameF) {
this.nameF = nameF;}
.
.
.
}
我做错了什么?
要解决此问题,您要做的就是在每个字段中添加注释:
@SerializedName("id")
String idF;
@SerializedName("name")
String nameF;
List <DataObject>与List的类型相同。 对于数组解析,您应该编写以下代码:
List<DataObject> list2 = new ArrayList<DataObject>((DataObject[])g.fromJson(RET, DataObject[]));
for(int i = 0; i < list2.size(); i++) {
System.out.println(list2.get(i).getNameF());
}
而且,您还应该为解析器解释将哪个字段连接到哪个JSON参数。 如果使用GSON解析器,则可以编写注释。 或者对于杰克逊,您应该重命名您的吸气剂和塞特剂,正如评论中告诉您的那样。
注释应该看下:
class DataObject {
@SerializedName("id")
String idF;
}
并用JSON字符串写在方括号字段名称中
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