Android Java传递XML解析器

Question

我已经编写了一个程序来从Eclipse中的XML文件中获取数据，并且已经打印到文本视图以确保尝试有效，但是它没有传递数据，但是我不确定是否ve输入了错误的参数，或者我打错了它，因此将不胜感激。

public class AnimalList extends Activity {
@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_animal_list);

    //pulls data from XML file
    XmlPullParserFactory pullParserFactory;
    try 
    {
        pullParserFactory = XmlPullParserFactory.newInstance();
        XmlPullParser parser = pullParserFactory.newPullParser();

            InputStream in_s = getApplicationContext().getAssets().open("animals.xml");
            parser.setFeature(XmlPullParser.FEATURE_PROCESS_NAMESPACES, false);
            parser.setInput(in_s, null);

            parseXML(parser);

            TextView display = (TextView)findViewById(R.id.animalInfo);
            display.setText("crap");

    } 
    catch (XmlPullParserException e) 
    {
        e.printStackTrace();


    } 
    catch (IOException e) 
    {
        //Auto-generated catch block
        e.printStackTrace();


    }
}

我知道以上通过打印到文本视图正在工作，但接下来我有

private void parseXML(XmlPullParser parser) throws XmlPullParserException,IOException
{
    ArrayList<Animal> animals = new ArrayList<Animal>();
    int eventType = parser.getEventType();
    Animal currentAnimal = null;


    while (eventType != XmlPullParser.END_DOCUMENT)
    {

        String name = null;
        switch (eventType)
        {
            case XmlPullParser.START_DOCUMENT:
                //animals = new ArrayList();
                break;
            case XmlPullParser.START_TAG:
                name = parser.getName();
                if (name == "animal")
                {
                    currentAnimal = new Animal();
                } 
                else if (currentAnimal != null)
                {
                    if (name == "specificLocation")
                    {
                        currentAnimal.specificLocation = parser.nextText();
                    } 
                    else if (name == "name"){
                        currentAnimal.name = parser.nextText();
                    } 
                    else if (name == "location")
                    {
                        currentAnimal.location= parser.nextText();
                    }  
                    else if (name == "image")
                    {
                        currentAnimal.image= parser.nextText();
                    }  
                    else if (name == "animalInfo")
                    {
                        currentAnimal.animalInfo= parser.nextText();
                    }  
                    else if (name == "todaysFeed")
                    {
                        currentAnimal.todaysFeed= parser.nextText();
                    }  
                }
                break;
            case XmlPullParser.END_TAG:
                name = parser.getName();
                if (name.equalsIgnoreCase("animal") && currentAnimal != null){
                    animals.add(currentAnimal);
                } 
        }
        eventType = parser.next();
    }

    printAnimals(animals);
}

然后其中的代码没有执行任何操作，因此希望有人指出我是否正确传递了它？ 在第二个步骤中，它只是将数据放入数组中，但是如果我在执行任何操作之前先放置文本视图输出，则它什么也没做，这使我认为它没有传递数据。

谢谢。

Answer 1

搜索标签名称您已经比较了引用，但没有比较字符串。 此外，它的工作正常。 因此parseXML将如下所示：

private void parseXML(XmlPullParser parser) throws XmlPullParserException,IOException
{
    ArrayList<Animal> animals = new ArrayList<Animal>();
    int eventType = parser.getEventType();
    Animal currentAnimal = null;


    while (eventType != XmlPullParser.END_DOCUMENT)
    {

        String name = null;
        switch (eventType)
        {
            case XmlPullParser.START_DOCUMENT:
                //animals = new ArrayList();
                break;
            case XmlPullParser.START_TAG:
                name = parser.getName();
                if (name.equalsIgnoreCase( "animal"))
                {
                    currentAnimal = new Animal();
                } 
                else if (currentAnimal != null)
                {
                    if (name.equalsIgnoreCase( "specificLocation"))
                    {
                        currentAnimal.specificLocation = parser.nextText();
                    } 
                    else if (name .equalsIgnoreCase( "name")){
                        currentAnimal.name = parser.nextText();
                    } 
                    else if (name .equalsIgnoreCase( "location"))
                    {
                        currentAnimal.location= parser.nextText();
                    }  
                    else if (name .equalsIgnoreCase( "image"))
                    {
                        currentAnimal.image= parser.nextText();
                    }  
                    else if (name .equalsIgnoreCase(  "animalInfo"))
                    {
                        currentAnimal.animalInfo= parser.nextText();
                    }  
                    else if (name .equalsIgnoreCase(  "todaysFeed"))
                    {
                        currentAnimal.todaysFeed= parser.nextText();
                    }  
                }
                break;
            case XmlPullParser.END_TAG:
                name = parser.getName();
                if (name.equalsIgnoreCase("animal") && currentAnimal != null){
                    animals.add(currentAnimal);
                } 
        }
        eventType = parser.next();
    }

    printAnimals(animals);
}   

希望对您有所帮助:) Marcin