联系表格php脚本将垃圾邮件发送到Gmail

Question

我创建了一个php脚本（用于联系表格）以将电子邮件发送到我的Gmail帐户。
如果我在标头（ $ headers =“ From：”。$ email; ）中使用发件人电子邮件，则Gmail会将收到的邮件报告为垃圾邮件。
如果我没有在标题中使用电子邮件（例如，发件人名称$ headers =“ From：”。$ name; ），则该邮件不会报告为垃圾邮件。
您是否有任何建议让我使用标题中的电子邮件？
谢谢！

<?php

/* Check if the url field is empty (antispam) */
if ($_POST['leaveblank'] != '' or $_POST['dontchange'] != 'http://') {
    $name = $_POST['name'];
    $faillink = "xxx.php";
    header("Location: $faillink");
} else {

    $name = $_POST['name'];
    $email = $_POST['email'];
    $subject_prefix = "[ContactForm]: ";
    $subject = $subject_prefix . $_POST['subject'];
    $message = $_POST['message'];
    $to = "myemail@gmail.com";

    $body = "From: " . $name . "\n";
    $body .= "Email: " . $email . "\n";
    $body .= "Message: " . $message . "\n";

    $headers = "From: " . $email;

    $oklink = "yyy.php";
    $faillink = "xxx.php";

    if ( preg_match( "/[\r\n]/", $name ) || preg_match( "/[\r\n]/", $email ) ) {
        header("Location: $faillink");
    }

    $retmail = mail($to, $subject, $body, $headers);
    if ($retmail) {
        header("Location: $oklink");
    } else {
        header("Location: $faillink");
    }
}

?>

Answer 1

我按照Iain的建议解决了这个问题，因此我按如下所示替换了邮件头：

$headers = "From: " . "noreplay@mydomain.com" . "\r\n";
$headres .= "Reply-To: " . $email . "\r\n";