[英]Getting only one row of a mysql table displayed using PHP
我目前有这段代码,可显示mysql表中的所有条目行,并将其显示在网页上;
<?php
$servername = "localhost";
$username = "appuser1";
$password = "*****";
$dbname = "acmefg_app";
$row = mysql_fetch_array(mysql_query("SELECT jobnumber FROM appdata WHERE id = '5608' LIMIT 1"));
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT id, jobnumber, assetnumber FROM appdata";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
echo "<br> id: ". $row["id"]. "<br>";
echo "<br> Job number: ". $row["jobnumber"]. "<br>";
echo "<br> Asset number: " . $row["assetnumber"] . "<br>";
}
} else {
echo "0 results";
}
$conn->close();
?>
我该如何更改,使其仅显示一个结果? 假设在这种情况下,我想显示ID为5611的行? 非常感谢
如果只显示一行,则无需使用while()
循环。 删除循环
if ($result->num_rows > 0) {
$row = $result->fetch_assoc();
echo "<br> id: ". $row["id"]. "<br>";
echo "<br> Job number: ". $row["jobnumber"]. "<br>";
echo "<br> Asset number: " . $row["assetnumber"] . "<br>";
}
或者可以在查询字符串中设置LIMIT 1。
SELECT id, jobnumber, assetnumber FROM appdata LIMIT 1
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