[英]How to remove double quotes and brackets from NSString
我有来自["658681","655917","655904"]
的字符串 我想以这种形式更改此字符串658681,655917,655904
如何更改它? 下面是我的字符串代码
- (IBAction)Searchbtn:(id)sender {
NSData *data=[NSJSONSerialization dataWithJSONObject:getmessageIDArray options:kNilOptions error:nil];
_finalIDStr=[[NSString alloc] initWithData:data encoding:NSUTF8StringEncoding];
NSLog(@"the final ID Str==%@",_finalIDStr);
}
这将在swift中完成
var stringwithoutquotes = string1.stringByReplacingOccurrencesOfString("\"", withString: "")
var removebracket1 = stringwithoutquotes.stringByReplacingOccurrencesOfString("[", withString: "")
var removebracket2 = removebracket1.stringByReplacingOccurrencesOfString("]", withString: "")
或者你可以在一行中完成整个事情
var string2 = string.stringByReplacingOccurrencesOfString("\"", withString: "").stringByReplacingOccurrencesOfString("[", withString: "").stringByReplacingOccurrencesOfString("]", withString: "")
这是swift中的另一个清洁选项
var string = "\"hello[]" // string starts as "hello[]
var badchar: NSCharacterSet = NSCharacterSet(charactersInString: "\"[]")
var cleanedstring: NSString = (string.componentsSeparatedByCharactersInSet(badchar) as NSArray).componentsJoinedByString("")
//cleanedstring prints as "hello"
斯威夫特3:
let string = "\"hello[]" // string starts as "hello[]
let badchar = CharacterSet(charactersIn: "\"[]")
let cleanedstring = string.components(separatedBy: badchar).joined()
//cleanedstring prints as "hello"
使用以下代码:
NSCharacterSet *unwantedChars = [NSCharacterSet characterSetWithCharactersInString:@"\"[]"];
NSString *requiredString = [[_finalIDStr componentsSeparatedByCharactersInSet:unwantedChars] componentsJoinedByString: @""];
这是从一行中删除字符串中的多个字符的高效且有效的方法。
Swift 4(String Array)我想将String Array转换为String文本放在TextView中:
从
[ “马”, “猫”, “狗”]
至
马
猫
狗
var stringArray = ["horse","cat","dog"]
var stringArrayCleaned = stringArray.description.replacingOccurrences(of: "\"", with: "").replacingOccurrences(of: ",", with: "\n").replacingOccurrences(of: "[", with: "").replacingOccurrences(of: "]", with: "").replacingOccurrences(of: " ", with: "")
print(stringArrayCleaned)
你可以试试 :
[[[_finalIDStr stringByReplacingOccurrencesOfString:@"\"" withString:@""] stringByReplacingOccurrencesOfString:@"[" withString:@""] stringByReplacingOccurrencesOfString:@"]" withString:@""];
我知道这是一个老问题,但万一有人还在寻找答案。我在 swift 中使用joined(separator:)
实现了这一点,请参阅: 苹果文档
var stringArray = ["alice","bob","cindy"]
print(stringArray.joined(separator: ","))
// this will print: alice,bob,cindy
NSString *str = ["658681","655917","655904"];
NSCharacterSet *cs = [NSCharacterSet characterSetWithCharactersInString:@"\"[]"];
str = [[string componentsSeparatedByCharactersInSet:cs] componentsJoinedByString:@""];
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