PHP通过两次选择遍历mysql结果并创建对齐的html表

Question

我在创建在PHP中像这样对齐的表时遇到了问题：

 TH   HOME                               AWAY
 TH | num    | name    | teamname |    | num    | name    | teamname |
 TR | hsknum | hskname | hsktname |    | asknum | askname | asktname |

我发现无法获得两个结果以foreach或while循环在表中对齐。

编辑2：

HOME或AWAY可能为空，或1-> 14个条目（HOME或AWAY的结果），这就是我的代码技能瓦解的地方。

谢谢。

编辑1：

我的PHP循环是：

<?php while (( $resultshome = $rowh->fetch()) || ($resultsaway = $rowa->fetch())) { ?>
                <tr>
                    <td>
                    <?php
                       if ( !empty($resultshome) ) { ?>
                      <?php echo $resultshome['hsknum']; ?>
                    </td>
                    <td>
                      <a href="/runner/profiles/runnerprofile.php?runnerid=<?php echo $resultshome['hskid']; ?>"><?php echo $resultshome['hskname']; ?></a>
                    </td>
                    <td>
                      <?php echo $resultshome['hsktname']; ?>
                    </td>
            <td>
            </td>
            <td>
            </td>
                <?php
                }
                else {
                echo "<td></td><td></td><td></td><td></td>";
                } ?>
                    <td>
                    <?php
                    if ( !empty($resultsaway) ) { ?>
                      <?php echo $resultsaway['asknum']; ?>
                    </td>
                    <td>
                      <a href="/runner/profiles/runnerprofile.php?runnerid=<?php echo $resultsaway['askid']; ?>"><?php echo $resultsaway['askname']; ?></a>
                    </td>
                    <td>
                      <?php echo $resultsaway['asktname']; ?>
                    </td>
                </tr>
                <?php
                }
                else {
                echo "<td></td><td></td>";
                } ?>
                <?php } ?>
            </table>

Answer 1

我想你想打开：

while (( $resultshome = $rowh->fetch()) && ($resultsaway = $rowa->fetch()))

PHP会使布尔语句短路，这意味着在（A || B）情况下，仅当“ A”的值为假时，才可以到达“ B”。 只要条件之间具有OR，就可以在开始$ rowa之前遍历所有$ rowh。

Answer 2

我稍微整理了一下代码，然后将任务移出了循环。

<table>
<?php 
$keys = [
    "home" => [
        'hsknum',
        'hskid',
        'hskname',
        'hsktname',
    ],
    "away" => [
        'asknum',
        'askid',
        'askname',
        'asktname',
    ],
];
$myFunc = function($row, $inArray, $team) use ($keys) {
    if (!empty($inArray)) {
        array_push(
            $row, 
            $inArray[$keys[$team][0]], 
            sprintf(
                '<a href="/runner/profiles/runnerprofile.php?runnerid=%s">%s</a>',
                $inArray[$keys[$team][1]],
                $inArray[$keys[$team][2]]
            ),
            $inArray[$keys[$team][3]],
            "&nbsp;",
            "&nbsp;"
        );
    } else {
        $row = array_merge($row, array_fill(0, 5, "&nbsp;"));
    }
    return $row;
};
do {
    $resultshome = $rowh->fetch();
    $resultsaway = $rowa->fetch();
    if (!$resultshome && !$resultsaway) {
        break;
    }
    $row = [];
    $row = $myFunc($row, $resultshome, "home");
    $row = $myFunc($row, $resultsaway, "away");
    echo "<tr><td>", implode("</td><td>", $row), "</td></tr>";
} while (true);
?>
</table>

编辑：现在有了home和away阵列键...

我对此游戏一无所知，但数据库应该像这样：

game
    id
    homeTeamId
    awayTeamId
    fromDate
    toDate

team
    id
    name

player
    id
    name

team_player
    teamId
    playerId
    fromDate
    toDate

team_game_players
    gameId
    teamId
    playerId
    number?

game_score
    gameId
    teamId
    playerId
    something?

Answer 3

更好的结构是将获取逻辑与显示逻辑分开。 如果两个查询都可以返回不同的行数（例如10个主场比赛对5个客场比赛），则尤其如此

$games = array();
$row = 0;
# fetch home game data
while($row = $rowh->fetch()) {
   $games[$row] = array(); // initialize this array row
   $games[$row]['home'] = $row;
   $row++;
}

$row = 0;
# fetch away game data
while($row = $rowa->fetch()) {
   $games[$row]['away'] = $row;
   $row++;
}

foreach ($games as $index => $game) {
if (isset($game['home']) { 
    ... output home stuff ...
} else {
    ... output empty cells - no home game for this particular row
}
if (isset($game['away']) {
    ... output away stuff
} else {
   ... output empty cells - no away game for this particular row
}