[英]Extract Data for 2 years and convert number to month
我有下表,其中月和年分开,我想加入以创建日期(因为我没有日,可以将其设置为第一个)
Measurement mm yyyy 15000 1 2014 16000 2 2014 15000 5 2013 16000 3 2014 15000 4 2014 16000 5 2014 15000 6 2013 16000 7 2012
所以我想输出为:
15000 01/01/2014
16000 01/02/2014
等等
仅最近两年。
这可能吗?
谢谢
SELECT Measurement,DT FROM
(
SELECT Measurement,DENSE_RANK() OVER(ORDER BY YYYY DESC) RNK,
CONVERT(varchar(11),'01'+'/'+CAST(MM AS VARCHAR(2))+'/'+CAST(YYYY AS VARCHAR(4)),103) DT
FROM #TEMP
)TAB
WHERE RNK IN(1,2)
更新
我正在根据您的新要求进行更新
在这里,我们将获得所有月份和与您一起LEFT JOIN
表格
;WITH CTE1 AS
(
SELECT 1 ID, CAST('01/01/2013' AS DATE) DT
UNION ALL
SELECT ID+1,DATEADD(MONTH,1,DT) FROM CTE1
WHERE ID<12
)
SELECT ID,DATENAME(MONTH,DT) [MONTH],TP.*,
DENSE_RANK() OVER(ORDER BY YYYY DESC) RNK
INTO #NEWTABLE
FROM CTE1
LEFT JOIN TEMP TP ON CAST(TP.MM AS NUMERIC(3,0)) = CAST(CTE1.ID AS NUMERIC(3,0))
现在我们声明2个变量,第一个变量获取值以将月份的行显示为列,第二个变量将NULL with zero
替换NULL with zero
DECLARE @cols NVARCHAR (MAX)
DECLARE @NullToZeroCols NVARCHAR (MAX)
SELECT @cols = COALESCE (@cols + ',[' + [MONTH] + ']',
'[' + [MONTH] + ']')
FROM (SELECT DISTINCT ID,[MONTH] FROM #NEWTABLE) PV
ORDER BY ID
SET @NullToZeroCols = SUBSTRING((SELECT ',ISNULL(['+[MONTH]+'],0) AS ['+[MONTH]+']'
FROM(SELECT DISTINCT [MONTH],ID FROM #NEWTABLE GROUP BY [MONTH],ID)TAB
ORDER BY ID FOR XML PATH('')),2,8000)
现在,我们选择表格中的最近两年并对其进行调整
DECLARE @query NVARCHAR(MAX)
SET @query = 'SELECT yyyy,' + @NullToZeroCols + ' FROM
(
SELECT yyyy, [MONTH], Measurement FROM #NEWTABLE
WHERE RNK IN(1,2)
) x
PIVOT
(
SUM(Measurement)
FOR [MONTH] IN (' + @cols + ')
) p
WHERE yyyy IS NOT NULL
ORDER BY yyyy;'
EXEC SP_EXECUTESQL @query
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