[英]Mysql - How to get all records being in other column in the same table
我有一个这样的表(mytable):
+------------+-----------+----------------+
| id_mytable | id_artist | foreing_column |
+------------+-----------+----------------+
| 1 | 2 | 5 |
| 2 | 1 | 5 |
| 3 | 1 | 2 |
| 4 | 3 | 6 |
+------------+-----------+----------------+
但是我只知道foreign_column列的数字5,知道这个5,我可以得到所有的id_artist(在这种情况下为2和1)
SELECT id_artist FROM `artist_band` WHERE id_band= 5
所以现在的问题是,在这种情况下,我想获取两个id_artist(1,2)的foreign_column,所以我将得到此表:
+------------+-----------+----------------+
| id_mytable | id_artist | foreing_column |
+------------+-----------+----------------+
| 1 | 2 | 5 |
| 2 | 1 | 5 |
| 3 | 1 | 2 |
+------------+-----------+----------------+
(您知道所有2和所有1都在foreign_column中)
我已经尝试过这样的事情:
(SELECT id_artist FROM `artist_band` as one WHERE id_band= 5)
inner join
(SELECT * FROM `artist_band` as two )
on one.id_artist = two.id_artist
要么:
SELECT * FROM `artist_band` where id_artist =
(SELECT id_artist FROM `artist_band` WHERE id_band= 5)
谢谢。
SELECT *
FROM mytable
WHERE id_artist
IN
(
SELECT id_artist
FROM mytable
WHERE foreign_column = 5 -- (or whatever)
)
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