[英]C Convert decimal scanf input to binary array
我正在开发一个程序,以使我的RaspPi驱动旧的HP十六进制支付。 我目前正在使用大小写/开关选项来控制GPIO输出选择。 我想使用直接二进制输入。 如何将十进制的scanf()输入转换为二进制数组?
#include <stdio.h>
#include <stdlib.h>
#include <wiringPi.h>
int main()
{
int displayNumber;
wiringPiSetup();
pinMode(0, OUTPUT);
pinMode(1, OUTPUT);
pinMode(2, OUTPUT);
pinMode(3, OUTPUT);
pinMode(6, OUTPUT);
digitalWrite(0, LOW);
digitalWrite(1, LOW);
digitalWrite(2, LOW);
digitalWrite(3, LOW);
digitalWrite(6, LOW);
printf("Please select a number to display! 0-9\n");
scanf("%i", &displayNumber);
switch (displayNumber) {
case 0:
digitalWrite(6, LOW);
digitalWrite(3, LOW);
digitalWrite(0, LOW);
digitalWrite(1, LOW);
digitalWrite(2, LOW);
digitalWrite(6, HIGH);
break;
case 1:
digitalWrite(6, LOW);
digitalWrite(3, HIGH);
digitalWrite(0, LOW);
digitalWrite(1, LOW);
digitalWrite(2, LOW);
digitalWrite(6, HIGH);
break;
case 2:
digitalWrite(6, LOW);
digitalWrite(3, HIGH);
digitalWrite(0, LOW);
digitalWrite(1, LOW);
digitalWrite(2, LOW);
digitalWrite(6, HIGH);
// code
break;
case 3:
digitalWrite(6, LOW);
digitalWrite(3, HIGH);
digitalWrite(0, HIGH);
digitalWrite(1, LOW);
digitalWrite(2, LOW);
digitalWrite(6, HIGH);
// Code
break;
case 4:
digitalWrite(6, LOW);
digitalWrite(3, LOW);
digitalWrite(0, LOW);
digitalWrite(1, HIGH);
digitalWrite(2, LOW);
digitalWrite(6, HIGH);
break;
case 5:
digitalWrite(6, LOW);
digitalWrite(3, HIGH);
digitalWrite(0, LOW);
digitalWrite(1, HIGH);
digitalWrite(2, LOW);
digitalWrite(6, HIGH);
break;
case 6:
digitalWrite(6, LOW);
digitalWrite(3, LOW);
digitalWrite(0, HIGH);
digitalWrite(1, HIGH);
digitalWrite(2, LOW);
digitalWrite(6, HIGH);
break;
case 7:
digitalWrite(6, LOW);
digitalWrite(3, HIGH);
digitalWrite(0, HIGH);
digitalWrite(1, HIGH);
digitalWrite(2, LOW);
digitalWrite(6, HIGH);
break;
case 8:
digitalWrite(6, LOW);
digitalWrite(3, LOW);
digitalWrite(0, LOW);
digitalWrite(1, LOW);
digitalWrite(2, HIGH);
digitalWrite(6, HIGH);
break;
case 9:
digitalWrite(6, LOW);
digitalWrite(3, HIGH);
digitalWrite(0, LOW);
digitalWrite(1, LOW);
digitalWrite(2, HIGH);
digitalWrite(6, LOW);
break;
}
return 0;
}
将switch语句替换为
digitalWrite(6, LOW);
digitalWrite(3, displayNumber & 1 ? HIGH : LOW);
digitalWrite(0, displayNumber & 2 ? HIGH : LOW);
digitalWrite(1, displayNumber & 4 ? HIGH : LOW);
digitalWrite(2, displayNumber & 8 ? HIGH : LOW);
digitalWrite(6, HIGH);
阅读本文:
#include<stdio.h>
#include<conio.h>
int main()
{
int d[20];
int decimalno,i=0;
printf("Enter the decimal number you want to conver to binary: \n");
scanf("%d",&decimalno);
while(decimalno>0)
{
d[i]=decimalno%2;
i++;
decimalno=decimalno/2;
}
printf("The binary version of the number you input, %d, is = ",decimalno);
for(int j=i-1;j>=0;j--)
{
printf("%d",d[j]);
}
//getch();
return 0;
}
我认为这是您的解决方案,因为您可以直接写入位,所以不需要数组
int main()
{
int displayNumber;
int pins[6] = {3, 0, 1, 2};
int i;
wiringPiSetup();
pinMode(0, OUTPUT);
pinMode(1, OUTPUT);
pinMode(2, OUTPUT);
pinMode(3, OUTPUT);
pinMode(6, OUTPUT);
digitalWrite(0, LOW);
digitalWrite(1, LOW);
digitalWrite(2, LOW);
digitalWrite(3, LOW);
digitalWrite(6, LOW);
displayNumber = -1;
while ((displayNumber < 0) || (displayNumber > 9))
{
printf("Please select a number to display! 0-9\n");
scanf("%i", &displayNumber);
}
digitalWrite(6, LOW);
for (i = 0 ; i < 4 ; i++)
digitalWrite(pins[i], displayNumber & (1 << i) ? HIGH : LOW);
digitalWrite(6, HIGH);
return 0;
}
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