[英]Update tinyint(1)
我想更新状态值-tinyint(1)-以激活和停用用户。 每当我尝试更新时,我都会不断收到以下消息,该消息设置为“话务员更新失败”。 任何帮助都感激不尽。 谢谢
if (empty($errors)) {
// Perform Update
$id = $attendant["id"];
$status = mysql_prep($_POST["status"]);
$query = "UPDATE attendant SET ";
$query .= "status = '{$status}', ";
$query .= "WHERE id = {$id} ";
$query .= "LIMIT 1";
$result = mysqli_query($connection, $query);
if ($result && mysqli_affected_rows($connection) == 1) {
// Success
$_SESSION["message"] = "Attendant updated.";
redirect_to("activate_attendant.php");
} else {
// Failure
$_SESSION["message"] = "Attendant update failed.";
}
}
} else {
// This is probably a GET request
}
删除status = '{$status}',
后的逗号status = '{$status}',
<=
MySQL通过执行以下操作会向您抛出错误:
$result = mysqli_query($connection, $query) or die(mysqli_error($connection));
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