[英]Uploading url file to remote server using curl
我已经使用了3天,但似乎无法解决,用户将输入url,系统会将其上传到远程服务器上。这是我到目前为止所做的
$POST_DATA = array(
'file' => '@'. 'http://images.visitcanberra.com.au/images/canberra_hero_image.jpg',
'extension' => 'txt',
'filename' => 'test',
'directory' => 'uploads/'
);
$curl = curl_init();
curl_setopt($curl, CURLOPT_URL, 'http://1234.4321.67.11/upload.php');
curl_setopt($curl, CURLOPT_TIMEOUT, 30);
curl_setopt($curl, CURLOPT_POST, 1);
curl_setopt($curl, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($curl, CURLOPT_POSTFIELDS, $POST_DATA);
$response = curl_exec($curl);
curl_close ($curl);
用这种方式做得好。
这可能会帮助您使用cURL在服务器上上传图像: https : //stackoverflow.com/a/15177543/1817160
这可能有助于您了解如何从url下载图像: 通过HTTP从远程服务器复制图像
使用以下功能通过curl上传远程图像。 通过将图像url和路径传递到文件夹来调用此命令以保存图像。
function grab_image($url,$saveto){
$ch = curl_init ($url);
curl_setopt($ch, CURLOPT_HEADER, 0);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_BINARYTRANSFER,1);
$raw=curl_exec($ch);
curl_close ($ch);
if(file_exists($saveto)){
unlink($saveto);
}
$fp = fopen($saveto,'x');
fwrite($fp, $raw);
fclose($fp);
}
并确保在php.ini中启用allow_url_fopen
$file_name_with_full_path = realpath('./upload/example.png');
$curl_handle = curl_init("https://example.com");
curl_setopt($curl_handle, CURLOPT_POST, 1);
$args['file'] = new CurlFile($file_name_with_full_path, 'image/png');
curl_setopt($curl_handle, CURLOPT_POSTFIELDS, $args);
curl_setopt($curl_handle, CURLOPT_RETURNTRANSFER, true);
$returned_data = curl_exec($curl_handle);
curl_close ($curl_handle);
echo $returned_data;
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