[英]IF statement on database query wont execute
<?php
if(empty($_POST) === false){
$required_fields = array('teacher_id','class_id','startyr','endyr');
foreach($_POST as $key=>$value){
if(empty($value) && in_array($key, $required_fields)===true){
$errors[]='Fields marked with an asterisk are required';
break 1;
}
}if(empty($errors)===true){
if(sched_exists($_POST['class_id'],$_POST['teacher_id'],$_POST['student_id']) === true){
$errors[]='Schedule Already Exist!';
}
}
}
?>
<div class="container alert" id="showError">
<?php
if(empty($_POST) === false && empty($errors) === true){
$cl_id=mysqli_real_escape_string($_POST['class_id']);
$teacher_id=mysqli_real_escape_string($_POST['teacher_id']);
$student_id=mysqli_real_escape_string($_POST['student_id']);
$startyr=mysqli_real_escape_string($_POST['startyr']);
$endyr=mysqli_real_escape_string($_POST['endyr']);
$q="INSERT INTO sched(cl_id,teacher_id,student_id,startyr,endyr)
values('{$cl_id}','{$teacher_id}','{$student_id}','{$startyr}','{$endyr}')";
mysqli_query($q)or die(mysqli_error());
mysqli_close($dbcon);
?>
<div class="alert alert-success">
<?php
echo "<strong>Successfully Created!</strong> ";
?>
</div>
<?php
}else{
echo output_errors($errors);
}
?>
</div>
function sched_exists($cl_id,$teacher_id,$student_id){
$cl_id;
$teacher_id;
$student_id;
return (mysql_result(mysql_query("SELECT COUNT(`sched_id`) FROM `sched` WHERE `cl_id` = '$cl_id' AND `teacher_id` = '$teacher_id'"),0)==1) ? true : false or die(mysql_error());
}
你能告诉我怎么了吗? 查询数据库的if语句将不会执行,如果我删除了sched的if语句,则查询将执行。 我不知道是什么问题。 请帮帮我
empty($ _ POST)永远不会为假。 最好询问if ( count($_POST) == 0)
mysql_result(result,0)
返回结果第一行第一列的值。 除非碰巧第一行是一个ID列,并且第一个结果恰好具有一个ID 1
否则该值可能不是1。您确实应该执行以下操作:
$result = mysql_query(/*your query*/);
if ($result) return true;
else return false;
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