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使用ShowDialog()从STA线程显示窗口

[英]Displaying Window from STA Thread using ShowDialog()

我需要从dll项目中打开一个窗口(在后台运行或在调用时触发)。 为此,我需要使用标记为[STAThread]的方法打开一个窗口以创建该窗口的实例。

我正在使用MVVM模式将ViewModel绑定到视图,并且该视图作为用户控件添加到MainWindow。

在“视图”上,有一个按钮绑定到“关闭”窗口的命令。 ViewModel中的命令调用CloseCommand(),后者又将调用window.Close()方法。

代码段:

    MethodShowingTheWindow() {
        var idVM = new IDWindowViewModel();
        ShowForm<MainWindow>(idVM); // Works fine, Close Command closes the window.
        ShowForm<MainWindow>(idVM); // hits the ShowDialog() line, then just jumps to the while loop 
        ShowForm<MainWindow>(idVM);        // waiting for the thread to finish. Never displays the window.
        ShowForm<MainWindow>(idVM);

    }

    [STAThread]
    public void ShowForm<T>(IViewModel vm) {
        Thread th = new Thread(new ThreadStart(delegate {
            var window = new MainWindow();
            window.DataContext = vm;

            vm.CloseAction = new Action(() => window.Close()); // Does this when the Close Action is called from the viewmodel (Close the window).

            try {
                window.ShowDialog();
            } catch (Exception ex) {
                throw ex;
            }
        }));

        th.ApartmentState = ApartmentState.STA;
        th.Start();

        while (th.IsAlive) {
            //Wait for thread to finish
        }
    }

我只需要知道为什么窗口不会在第二次ShowWindow(idVM)调用中出现? 我能想到的是,窗口没有正确关闭/处理。 我尝试将以下内容添加到CloseAction操作中:

...
vm.CloseAction = new Action(() => {
    if (window is IDisposable) (window as IDisposable).Dispose();
    window.Close();
});

但是(窗口是IDisposable)==假?

任何帮助将不胜感激。

这是我为您设计的方案。 使用分派器以避免STA异常:

async Task MethodShowingTheWindow() 
{
    var idVM = new IDWindowViewModel();
    await ShowForm<MainWindow>(idVM); // Works fine, Close Command closes the window.
    await ShowForm<MainWindow>(idVM); // hits the ShowDialog() line, then just jumps to the while loop 
    await ShowForm<MainWindow>(idVM);        // waiting for the thread to finish. Never displays the window.
    await ShowForm<MainWindow>(idVM);
}

public await Task ShowForm<T>(IViewModel vm) 
{
    Dispatcher.InvokeAsync(() =>
    {
        var window = new MainWindow();
        window.DataContext = vm;
        System.Windows.Application.Current.Dispatcher.Invoke(() =>
        {
            vm.CloseAction = new Action(() => window.Close());
        });
        window.ShowDialog();
    });
}

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