Apache2 ModSecurity2不起作用（Ubuntu 14.04）

Question

我遵循wiki.ubuntuusers.de上的官方文档，但是我的test.php文件仍然允许恶意访问，例如test.php？secret_file = my / secret / file.txt。 想法为什么？

test.php的：

<?php
    $secret_file = $_GET['secret_file'];
    include ( $secret_file);
?>

test.php？secret_file = my / secret / file.txt的预期结果是HTTP 403-访问被拒绝，但是我的Web服务器仍显示包含文件的内容。

我的安装步骤：

sudo apt-get install libapache2-mod-security2
sudo a2enmod security2
sudo a2enmod headers

Configuration

sudo cp /etc/modsecurity/modsecurity.conf-recommended /etc/modsecurity/modsecurity.conf

# Enable ModSecurity, attaching it to every transaction. Use detection
# only to start with, because that minimises the chances of post-installation
# disruption.
#
#SecRuleEngine DetectionOnly
#
SecRuleEngine On                                   

Include /usr/share/modsecurity-crs/*.conf
Include /usr/share/modsecurity-crs/base_rules/*.conf
Include /usr/share/modsecurity-crs/optional_rules/*.conf

SecDebugLog /var/log/apache2/modsec_debug.log
SecDebugLogLevel 5

sudo service apache2 restart
sudo service apache2 force-reload 

这是我的modsec_debug.log文件： modsec_debug.log

当我致电恶意test.php？secret_file = my / secret / file.txt时，它说：

[Sun Jan 25 13:21:51.773188 2015] [:error] [pid 14993] [client x.x.x.x] ModSecurity: Warning. Match of "eq 1" against "&ARGS:CSRF_TOKEN" required. [file "/usr/share/modsecurity-crs/optional_rules/modsecurity_crs_43_csrf_protection.conf"] [line "31"] [id "981143"] [msg "CSRF Attack Detected - Missing CSRF Token."] [hostname "example.com"] [uri "/test.php"] [unique_id "VMTf31XWGY4AADqRE00AAAAB"]

[Sun Jan 25 13:21:51.777069 2015] [:error] [pid 14993] [client x.x.x.x] ModSecurity: Warning. Operator LT matched 5 at TX:inbound_anomaly_score. [file "/usr/share/modsecurity-crs/base_rules/modsecurity_crs_60_correlation.conf"] [line "33"] [id "981203"] [msg "Inbound Anomaly Score (Total Inbound Score: 3, SQLi=0, XSS=0): Request from Known SPAM Source (Previous RBL Match)"] [hostname "example.com"] [uri "/test.php"] [unique_id "VMTf31XWGY4AADqRE00AAAAB"]

[Sun Jan 25 13:21:51.777133 2015] [:error] [pid 14993] [client x.x.x.x] ModSecurity: Warning. Match of "rx (?i:(<meta.*?(content|value)=\\"text/html;\\\\s?charset=|<\\\\?xml.*?encoding=))" against "RESPONSE_BODY" required. [file "/usr/share/modsecurity-crs/optional_rules/modsecurity_crs_55_application_defects.conf"] [line "23"] [id "981220"] [msg "[Watcher Check] No charset was specified in the HTTP Content-Type header nor the HTML content's meta tag."] [data "Content-Type Response Header: text/html"] [tag "WASCTC/WASC-15"] [tag "APP_DEFECT/MISCONFIGURATION"] [tag "http://code.google.com/p/browsersec/wiki/Part2#Content_handling_mechanisms"] [hostname "example.com"] [uri "/test.php"] [unique_id "VMTf31XWGY4AADqRE00AAAAB"]

[Sun Jan 25 13:21:51.777193 2015] [:error] [pid 14993] [client x.x.x.x] ModSecurity: Warning. Match of "rx (<meta.*?(content|value)=\\"text/html;\\\\s?charset=utf-8|<\\\\?xml.*?encoding=\\"utf-8\\")" against "RESPONSE_BODY" required. [file "/usr/share/modsecurity-crs/optional_rules/modsecurity_crs_55_application_defects.conf"] [line "36"] [id "981222"] [msg "[Watcher Check]  The charset specified was not utf-8 in the HTTP Content-Type header nor the HTML content's meta tag."] [data "Content-Type Response Header: text/html"] [tag "WASCTC/WASC-15"] [tag "MISCONFIGURATION"] [tag "http://websecuritytool.codeplex.com/wikipage?title=Checks#charset-not-utf8"] [hostname "example.com"] [uri "/test.php"] [unique_id "VMTf31XWGY4AADqRE00AAAAB"]

Answer 1

modsecurity_crs_43_csrf_protection.conf上的规则正在查找CSRF攻击，但是，您尝试执行的规则不是CSRF。

你可以试试看

1. 从/etc/apache2/mods-enabled/security2.conf删除Include /usr/share/modsecurity-crs/base_rules/*.conf和Include /usr/share/modsecurity-crs/optional_rules/*.conf /etc/apache2/mods-enabled/security2.conf （我猜您正在使用Ubuntu）。
2. 在/etc/modsecurity/modsecurity_crs_15_customrules.conf创建规则集
3. 将此规则包含在该文件中SecRule REQUEST_URI "secret" "phase:1,t:none,log,deny,id:'9000070001',msg:'Malicious content blocked'"
4. 运行sudo service apache2 restart

尝试从浏览器中访问相同的URL，观看/var/log/apache2/modsec_audit.log，让我知道它的运行方式。

谢谢，

丹尼尔