如果某一列包含特定值，则选择具有相同ID的所有行

Question

我有一张表，大致如下：

Runners Leagues  Matches   Line   InDict

Team 1  LeagueA  Match 1  Line 1   'Yes'
Team 2  LeagueA  Match 1  Line 1   'Yes'
Team 3  LeagueA  Match 1  Line 1   'No'
Team 1  LeagueA  Match 4  Line 1   'Yes'
Team 2  LeagueA  Match 4  Line 1   'Yes'
Team 1  LeagueA  Match 1  Line 2   'Yes'
Team 2  LeagueA  Match 1  Line 2   'Yes'
Team 3  LeagueA  Match 1  Line 2   'Yes'
Team 1  LeagueB  Match 5  Line 8   'No'
Team 2  LeagueB  Match 5  Line 8   'Yes'

我想做的是选择“联赛/比赛/线”列相同的所有行，如果其中之一在InDict列中包含“否”值。 因此，在上面的示例中，查询将返回：

Team 1  LeagueA  Match 1  Line 1   'Yes'
Team 2  LeagueA  Match 1  Line 1   'Yes'
Team 3  LeagueA  Match 1  Line 1   'No'
Team 1  LeagueB  Match 5  Line 8   'No'
Team 2  LeagueB  Match 5  Line 8   'Yes'

我是mysql的新手，因此正在努力为此目的找到正确的查询。

任何帮助是极大的赞赏！

Answer 1

这应该工作：

select * from tableName a where 
exists(select * from tableName b where 
b.league=a.league and 
b.matches=a.matches and 
b.line=a.line and 
b.inDict="No")

Answer 2

MySQL允许您在in运算符中使用多个列子查询：

select *
from TableName
where (Leagues,Matches,Line) in (
    select Leagues,Matches,Line
    from TableName
    where InDict='''No'''
)

http://sqlfiddle.com/#!2/ddf5c/1

Answer 3

select * from yourtable
where concat(leagues,Matche,line) in(
    select concat(leagues,Matche,line) as v
    from yourtable
    where InDict = 'No'
)