[英]get json data from URL using php
在这里,我尝试从以下网址获取json数据
自由软件网址 :http:
根据以上链接包含我想要获得的以下信息
{
"places": {
"place": [
{
"place_id": "Dm5SiT1TULMEIMYN",
"woeid": "2295402",
"latitude": 23.03,
"longitude": 72.591,
"place_url": "/India/Gujarat/Ahmedabad",
"place_type": "locality",
"place_type_id": 7,
"timezone": "Asia/Kolkata",
"_content": "Ahmedabad, Gujarat, India",
"woe_name": "Ahmedabad"
},
{
"place_id": "mz1zSK1YUrJTfvUrOA",
"woeid": "90883450",
"latitude": 23.027,
"longitude": 72.57,
"place_url": "/India/Gujarat",
"place_type": "locality",
"place_type_id": 7,
"timezone": "Asia/Kolkata",
"_content": "Ahmedabad, India",
"woe_name": "Ahmedabad"
}
],
"query": "Ahmedabad, Gujarat, India",
"total": 2
},
"stat": "ok"
}
但这里的问题是这个链接返回null我正在使用下面的PHP代码
$json_array = file_get_contents("https://www.flickr.com/services/api/render?method=flickr.places.find&api_key=xxxxx&query=Ahmedabad,%20Gujarat,%20India&format=json&nojsoncallback=1");
$json_array = iconv('UTF-16', 'UTF-8', $json_array);
$json_data=json_decode($json_array,true);
print_r($json_data);
你的电话是错的。 正确的是
https://api.flickr.com/services/rest/?method=flickr.places.find&.....
我发现它,因为你正在调用/api/render
方法,所以它会给出pretty printed
json
只需使用此网址即可
//https://www.flickr.com/services/rest?method=flickr.places.find&api_key=c5336c8cc248142bbda940c1f771bfd5&query=Ahmedabad,%20Gujarat,%20India&format=json&nojsoncallback=1
$json_array = file_get_contents("https://www.flickr.com/services/rest?method=flickr.places.find&api_key=c5336c8cc248142bbda940c1f771bfd5&query=Ahmedabad,%20Gujarat,%20India&format=json&nojsoncallback=1");
$json_data=json_decode($json_array,true);
print_r($json_data);
我尝试了来自Flickr API
的示例请求。
https://www.flickr.com/services/rest/?method=flickr.test.echo&format=json&foo=bar&api_key=cddc3ae537ed443aafa20cf2c30086df
您需要在请求URI中添加以下参数format=json
。 此外,端点必须是/services/rest
。
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