单击提交按钮时的PHP排序表

Question

我希望能够在单击“提交”按钮时将表按ASC排序。

我曾使用数组函数从SQL数据库获取信息，我曾尝试制作一个排序函数，但是当我单击“提交”时，什么也没发生。

这是我创建提交按钮的尝试：

 <h1> Courses </h1>
<form name="Table Properties" method="post" action="<?php echo $_SERVER['PHP_SELF']; ?>">
Order by Week
<button type="submit" name="week" class="button" <?php echo $value='1'; ?>"> Sort Week </button>
</form>
<?php 
if(isset($_POST['week'])){
        $query="SELECT * FROM `classes` ORDER BY `classes`.`week` ASC";
   }

当我单击提交时，表格保持不变。

这是我的表连接信息

$con = mysql_connect("host", "username", "password");
if (!$con) 
{
    die('Could not connect: ' . mysql_error());
}
mysql_select_db("username", $con);
$sql = "SELECT * FROM `classes`";
$myData = mysql_query($sql, $con);
echo "<table border=1>
<tr>
<th> Name 1 </th>
<th> Name 2 </th>
<th> Name 3 </th>
<th> Name 4 </th>
</tr>";
while ($record = mysql_fetch_array($myData)){
    echo "<tr>";
    echo"<td>" . $record['name 1'] . "</td>";
    echo"<td>" . $record['week'] . "</td>";
    echo"<td>" . $record['name 3'] . "</td>";
    echo"<td>" . $record['name 4'] . "</td>";
    echo "</tr>";
}
echo "</table>";
mysql_close($con);
}
?>

过去我曾问过类似的问题，但由于缺乏完整的信息，我认为它们被误解了。

Answer 1

您必须更改原始查询。 $sql = "SELECT * FROM classes";

让我们总结一下：

您的表格：

<h1> Courses </h1>
<form name="Table Properties" method="post" action="<?php echo $_SERVER['PHP_SELF']; ?>">
Order by Week
<button type="submit" name="week" class="button" <?php echo $value='1'; ?>"> Sort Week </button>
</form>

提交时：

<?php

$orderString = ''; // default 
if (isset($_POST['week'])){
    $orderString = "`classes`.`week` ASC";
}

您的显示：

$con = mysql_connect("host", "username", "password");
if (!$con) 
{
    die('Could not connect: ' . mysql_error());
}
mysql_select_db("username", $con);
$sql = "SELECT * FROM `classes`";
// now check order
if ($orderString !== '') {
    // Concatenate
    $sql .= ' ORDER BY ' . $orderString;
}
$myData = mysql_query($sql, $con);
echo "<table border=1>
<tr>
<th> Name 1 </th>
<th> Name 2 </th>
<th> Name 3 </th>
<th> Name 4 </th>
</tr>";
while ($record = mysql_fetch_array($myData)){
    echo "<tr>";
    echo"<td>" . $record['name 1'] . "</td>";
    echo"<td>" . $record['week'] . "</td>";
    echo"<td>" . $record['name 3'] . "</td>";
    echo"<td>" . $record['name 4'] . "</td>";
    echo "</tr>";
}
echo "</table>";
mysql_close($con);
}
?>

Answer 2

在“表连接信息”中的SQL语句中添加ORDER BY子句。

Answer 3

试试这个代码

$con = mysql_connect("host", "username", "password");
if (!$con) 
{
    die('Could not connect: ' . mysql_error());
}
mysql_select_db("username", $con);
$sql = "SELECT * FROM `classes`";

if(isset($_POST['week'])){
        $sql="SELECT * FROM `classes` ORDER BY `classes`.`week` ASC";
   }

$myData = mysql_query($sql, $con);
echo "<table border=1>
<tr>
<th> Name 1 </th>
<th> Name 2 </th>
<th> Name 3 </th>
<th> Name 4 </th>
</tr>";
while ($record = mysql_fetch_array($myData)){
    echo "<tr>";
    echo"<td>" . $record['name 1'] . "</td>";
    echo"<td>" . $record['week'] . "</td>";
    echo"<td>" . $record['name 3'] . "</td>";
    echo"<td>" . $record['name 4'] . "</td>";
    echo "</tr>";
}
echo "</table>";
mysql_close($con);
}
?>

Answer 4

您可以在按下提交按钮时定义您的操作，但实际上并不使用它。 您不需要填写表格后的php部分。 尝试编辑您的表连接信息：

...
mysql_select_db("username", $con);
if(isset($_POST['week'])){
    $sql="SELECT * FROM `classes` ORDER BY `classes`.`week` ASC";
}
else{
    $sql = "SELECT * FROM `classes`";
}
$myData = mysql_query($sql, $con);
...