加2个数字并使用Assembly x86打印结果

Question

我是Assembly x86 Learner的新手，我想添加两个数字（5 + 5）并将结果打印在屏幕上。

这是我的代码：

global _start

section .text
_start:
    mov eax, 5
    mov ebx, 5
    add eax, ebx
    push eax
    mov eax, 4 ; call the write syscall
    mov ebx, 1 ; STDOUT
    pop ecx    ; Result
    mov edx, 0x1
    int 0x80

    ; Exit
    mov eax, 0x1
    xor ebx, ebx
    int 0x80

请纠正我

Answer 1

将无符号整数转换为字符串并将其写入的另一种方法：

section .text
global _start
_start:

    mov eax, 1234567890
    mov ebx, 5
    add eax, ebx

    ; Convert EAX to ASCII and store it onto the stack
    sub esp, 16             ; reserve space on the stack
    mov ecx, 10
    mov ebx, 16
    .L1:
    xor edx, edx            ; Don't forget it!
    div ecx                 ; Extract the last decimal digit
    or dl, 0x30             ; Convert remainder to ASCII
    sub ebx, 1
    mov [esp+ebx], dl       ; Store remainder on the stack (reverse order)
    test eax, eax           ; Until there is nothing left to divide
    jnz .L1

    mov eax, 4              ; SYS_WRITE
    lea ecx, [esp+ebx]      ; Pointer to the first ASCII digit
    mov edx, 16
    sub edx, ebx            ; Count of digits
    mov ebx, 1              ; STDOUT
    int 0x80                ; Call 32-bit Linux

    add esp, 16             ; Restore the stack

    mov eax, 1              ; SYS_EXIT
    xor ebx, ebx            ; Return value
    int 0x80                ; Call 32-bit Linux