php：如何从多个下拉列表中将值插入数据库并添加一个文本

Question

我有两个表'用 2 个下拉列表显示了它的数据，所以我想从两个下拉列表中添加那些选定的值，并想插入一个问题（文本）和一个单选按钮值！ 请帮助我有点困惑：/怎么办？

这是代码

<div class="grid_10">
        <div class="box round first">

            <h2>Add / Edit Questions </h2>
            <p>         
            </p>
        </div>
    </div>
    <div class="grid_5">
        <div class="box round">
            <h2>
                Add / Update Questions</h2>
            <div class="block">
                <p>
<table style="width:100%">
<tr> 
    <td>
        <h2>Select Designation</h2>


<?php       

        $sql = "SELECT desg_name FROM 360d_designation";
        $ds = mysql_query($sql) or die(mysql_error());
        echo "<select>";
        while($row = mysql_fetch_array($ds)){
        echo "<option value='".$row["desg_id"]."'>".$row["desg_name"]."</option>";
        }mysql_free_result($ds);
        echo "</select>";



    ?>  

     </td>
    <td>        
        <h2>Select Relation 
        </h2> 
        <?php
            //<select id="id" name="selectstate" onChange="showCity(this.value)">
            $sql = "SELECT rel_name FROM 360d_relations";
            $rs = mysql_query($sql) or die(mysql_error());
            echo "<select>";
            while($row = mysql_fetch_array($rs)){
            echo "<option value='".$row["rel_id"]."'>".$row["rel_name"]."</option>";
            }mysql_free_result($rs);
            echo "</select>";  
            //$rel = $row;
        ?>
    </td>
</tr>

输入问题：

反馈方式

点刻度说明

 <?php if(isset($_POST["btns"])){ //<-----Inserting data in to databse $que_id = $_POST['que_id']; $Que_detail = $_POST['Que_detail']; $desg_id = $_POST['$ds']; $rel_id = $_POST['$rs']; $feedback_type = $_POST['$c1']; $msg=""; if($que_id==0) { $q = "insert into 360d_app_questions values(null,'{$Que_detail}','{$desg_id}','{$rel_id}','{$feedback_type}')"; $msg = "added"; } else { $q = "update 360d_app_questions set Que_detail ='{$Que_detail}' where que_id=".$que_id; $msg = "updated"; } $res = mysql_query($q,$con); if($res) echo "<h2>Question {$msg} sucessfully!!</h2>"; else echo "question cannot be {$msg}"; } ?> </center> </p> </div> </div> </div> <div class="grid_5"> <div class="box round"> <h2>View Questions </h2> <div class="block"> <p> <?php /* $qry = "select * from 360d_app_questions "; $res = mysql_query($qry,$con); if($res && mysql_num_rows($res)>0){ echo "<table cellspacing=10>". "<tr><th><h2>Questions Manager </h2></th><th><h2> &nbsp &nbsp Edit</h2></th><th></th></tr>"; while($row = mysql_fetch_array($res)){ echo "<tr>". "<td><h2>$row[1]</h2></td>". "<td><a href='360d_addquestions.php?dept_id={$row[0]}'> <h2>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;✉ <?php ?></h2></a></td>". "</tr>"; } echo "</table>"; */ ?> </p> </div> </div> </div> <div class="clear"> </div> </div> <div class="clear"> </div>

Answer 1

如果我理解你的标题问题，你应该给你两个选择一个名字，比如

<select name="test">
// Options here
</select>

<select name="test_2">
// Options here
</select>

要在 DB 上插入一些其他文本，我们可以通过不同的方式实现，一种是在您选择标签中执行以下操作：

echo "<option value='".$row["rel_id"]." / Details'>".$row["rel_name"]."</option>";

以及通过表单发送威胁数据的地方，您可以使用：

$exploded = explode('/', $_POST['test']);

然后你可以连接

或者您可以在插入数据库时​​插入文本，例如：

"INSERT INTO tableName(columnName) VALUES (value1+ ' ' + detail)"