提交表单后按钮颜色保持不变

Question

我在顶部有3个按钮，颜色给定。按下按钮它会改变颜色，表示按下了按钮，我的提交表单打开。一旦我提交表单消息显示“成功”。但我的问题是当我按下提交按钮时，顶部按钮颜色变为前一个但我希望它保持不变。我可以这样做，请帮助！ 这是我的代码：

这是我的javascript和css fr更改按钮颜色：

<script type="text/javascript">

    $(document).ready(function (){
   $('.beforeClick').click(function (){
       $('.beforeClick').css('background-color',"#C1B0B3");
           $(this).css('background-color',"#9C7260");
   });
});

<style>
.beforeClick {
   margin-left: 0.4%;
   background-color:#C1B0B3;
    font-weight: bold;
  width: 14em;  
  height: 2em;
}
</style>

这是我的按钮及其形式：

  <html>
        <body> 
     <button type="button" id="incbutton" class="beforeClick" style="background-color:#9C7260">Report1</button>

<button type="button" id="dthbutton"  class="beforeClick">Report2</button>

<button type="button" id="negbutton"  class="beforeClick"> Report3</button>


             <script type="text/javascript">
           $("#incbutton").click(function() {
            $("#form_sub_container1").show();
            $("#form_sub_container2").hide();
             $("#form_sub_container3").hide();
            })

            $("#dthbutton").click(function() {
            $("#form_sub_container2").show();
            $("#form_sub_container1").hide();
                $("#form_sub_container3").hide();
        })

        $("#negbutton").click(function() {
            $("#form_sub_container3").show();
            $("#form_sub_container1").hide();
                $("#form_sub_container2").hide();
        })
            </script>

           <div id="form_sub_container1" style="display:<?=  ( isset($_POST['rep']) || (!isset($_POST['report21']) && !isset($_POST['report31'])))? 'block':'none'?>">

        //report1 functionalities
        <input type="submit" name="rep" value="Save" id="btnsize1" /></td>
        </div>
          <div id="form_sub_container2" style="display: <?= isset($_POST['report21'])? 'block':'none'?>">

        //report2 functionalities
        <input type="submit" name="report21" value="Save" id="btnsize2" /></td>
        </div>

       <div id="form_sub_container3" style="display: <?= isset($_POST['report31'])? 'block':'none'?>">

        //report3 functionalities
        <input type="submit" name="report31" value="Save" id="btnsize3" /></td>
        </div>
        </body>
        <html>

这是我的报告3：

<div id="form_sub_container3" style="display: <?= isset($_POST['report31'])? 'block':'none'?>">
<?php


if (isset($_POST['report31'])) 
 {
    $daydropdown111=$_POST['daydropdown111'];
    $monthdropdown111=$_POST['monthdropdown111'];
    $yeardropdown111=$_POST['yeardropdown111'];
    $dreport_place=$_POST['dreport_place'];
    $dreport_address=$_POST['dreport_address'];
    $dreport_additional=$_POST['dreport_additional'];
 }
 else 
 {
    $daydropdown111="";
    $monthdropdown111="";
    $yeardropdown111="";
    $dreport_place ="";
    $dreport_address="";
    $dreport_additional="";
 }

if (isset($_POST['report31'])) 
{

    $death = $DataAccessController->death_reports($_POST['daydropdown111'],$_POST['monthdropdown111'],$_POST['yeardropdown111'],$_POST['dreport_place'], $_POST['dreport_address'], $_POST['dreport_additional']);
    if ($death) {
          echo"<p><font  color=red  size='5pt' > Your  Report has been Registered</font></p>";

        }

}


?>

<div id="color" >
    <table>

            <h1 align="center"><p> Report</h1>


    <form action="" method="POST" id="form_id">

        <tr><td>Date </td><td>
            <select name="daydropdown111" id="daydropdown111"></select> 
            <select name="monthdropdown111" id="monthdropdown111"></select>
            <select name="yeardropdown111" id="yeardropdown111"></select>
            <script type="text/javascript">
            //populatedropdown(id_of_day_select, id_of_month_select, id_of_year_select)

                    populatedropdown("daydropdown111", "monthdropdown111", "yeardropdown111")

            </script>

        </td></tr>

        <tr><td></br>  Place  </td><td></br><select name="dreport_place"id="wgtmsr">
        <option value="hospital" >Hospital</option><option value="residence">Residence</option><option value="others">Others</option></select></td></tr>

        <tr><td>Address  </td><td></br><textarea name="dreport_address" rows="5" cols="32" id="loc" value=""> </textarea></td></tr>

        <tr><td>Additional Cases if any</td><td></br> <textarea name="dreport_additional" rows="5" cols="32" id="loc" value=""> </textarea></td></tr></label></td></tr>

        <tr><td></td><td><input type="submit" name="report31" value="Save" id="btnsiz"   /></td></tr>


    </form>
    </table></br>
</div>
</div>

Answer 1

不，这就是你想要的？

 $(document).ready(function(){ $('.beforeClick').click(function(){ $(this).css('background-color',"#C1B0B3"); }); });

 <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script> <button type="button" id="incbutton" class="beforeClick" style="background-color:#9C7260" >Report1</button> <button type="button" id="dthbutton" class="beforeClick">Report2</button> <button type="button" id="negbutton" class="beforeClick">Report3</button>

Answer 2

创建一个类并.clickedButton调用它， 例如： .clickedButton或.afterClick ，然后在提交表单时，就像使用#form_sub_container divs一样：

<div id="form_sub_container3" style="display: <?= isset($_POST['report31'])? 'block':'none'?>">

但是这次你必须用你的按钮来做，比如：

<button type="button" id="incbutton" class="<?= isset($_POST['rep'])? 'afterClick':'beforeClick'?>" >Report1</button>
<button type="button" id="dthbutton" class="<?= isset($_POST['report21'])? 'afterClick':'beforeClick'?>" >Report2</button>
<button type="button" id="negbutton" class="<?= isset($_POST['report31'])? 'afterClick':'beforeClick'?>" >Report3</button>

CSS

.afterClick{
     background-color:#9C7260;
}

提交表单后按钮颜色保持不变

问题描述

2 个解决方案

解决方案1
0 2015-02-20 07:24:00

解决方案2
0 2015-02-20 13:12:00

提交表单后按钮颜色保持不变

问题描述

2 个解决方案

解决方案1 0 2015-02-20 07:24:00

解决方案2 0 2015-02-20 13:12:00

解决方案1
0 2015-02-20 07:24:00

解决方案2
0 2015-02-20 13:12:00