根据列的值获取MySQL表的列

Question

我正在尝试检索以下格式的表的列名：

id | error 1 | error 2 | error 3 | error 4 |
--------------------------------------------
 1 |    1    |    0    |    0    |    1    |
-------------------------------------------
 2 |    0    |    0    |    0    |    0    |

我需要检索值为1的列名。不是执行“从表中的id ='someid'中选择*”然后过滤掉，有没有办法直接从查询中击中列名？

Answer 1

虽然这会好得多只是做普通的SQL查询，然后在你的PHP代码处理数据，您可以使用CASE这里条款得到它在SQL完成：

SELECT id,
  ( CASE WHEN `error 1` = 1 THEN 'error 1' END ),
  ( CASE WHEN `error 2` = 1 THEN 'error 2' END ),
  ( CASE WHEN `error 3` = 1 THEN 'error 3' END ),
  ( CASE WHEN `error 4` = 1 THEN 'error 4' END )
  FROM your_table

Answer 2

SELECT id, CONCAT_WS(',',t2.e1,t2.e2,t2.e3,t2.e4) as err FROM table1
INNER JOIN (
  SELECT id, 
    CASE WHEN `error 1`= 1 THEN 'error 1' ELSE NULL END AS e1,
    CASE WHEN `error 2`= 1 THEN 'error 2' ELSE NULL END AS e2,
    CASE WHEN `error 3`= 1 THEN 'error 3' ELSE NULL END AS e3,
    CASE WHEN `error 4`= 1 THEN 'error 4' ELSE NULL END AS e4
  FROM table1

) as t2
on table1.id=t2.id