Fortran和C ++线程

Question

我有以下Fortran代码调用C ++函数parallel_klu 。 parallel_klu每次调用时都会创建八个线程（执行另一个名为factor函数），并在它返回Fortran之后线程被销毁。

program linkFwithCPP        
   use iso_c_binding
   implicit none 
   interface
   subroutine my_routine (Ax, Ai, Ap, b, n, nz) bind (C, name = "parallel_klu")
   import :: c_double
   import :: c_int
   integer (c_int), intent (out), dimension (*) :: Ap
   integer (c_int), intent (out), dimension (*) :: Ai
   real (c_double), intent (out), dimension (*) :: Ax
   real (c_double), intent (out), dimension (*) :: b
   integer(c_int), value :: n
   integer(c_int), value :: nz
   end subroutine
   end interface


   integer,parameter ::n=10
   integer,parameter ::nz=34

   ! declare the 4 arrays
   real (c_double), dimension (0:nz-1) :: Ax
   real (c_double), dimension (0:n-1) :: b
   integer (c_int), dimension (0:n) :: Ap
   integer (c_int), dimension (0:nz-1) :: Ai
   !Inputing array values
    open(unit = 1, file = 'Ax.txt')
    read(1,*) Ax         
    close(1)

    open(unit = 2, file = 'Ai.txt')
    read(2,*) Ai            
    close(2)

    open(unit = 3, file = 'Ap.txt')
    read(3,*) Ap            
    close(3)

    open(unit = 4, file = 'b.txt')
    read(4,*) b            
    close(4)


    ! Call C++ function
    call my_routine(Ax, Ai, Ap, b, n, nz)
    write (*, *) "Fortran: b:", b
    pause
 end program linkFwithCPP  

C ++中的函数如下：

 void parallel_klu(double Ax[], int Ai[], int Ap[], double b[], const int n, const int nz)
{
  threadList.push_back(std::thread(factor, Ap, Ai, Ax, b, Q, P, Pinv, n, 0, 5000));
  threadList.push_back(std::thread(factor, Ap, Ai, Ax, b, Q, P, Pinv, n, 5000, 10000));
  threadList.push_back(std::thread(factor, Ap, Ai, Ax, b, Q, P, Pinv, n, 10000, 15000));
  threadList.push_back(std::thread(factor, Ap, Ai, Ax, b, Q, P, Pinv, n, 15000, 20000));
  threadList.push_back(std::thread(factor, Ap, Ai, Ax, b, Q, P, Pinv, n, 20000, 25000));
  threadList.push_back(std::thread(factor, Ap, Ai, Ax, b, Q, P, Pinv, n, 25000, 30000));
  threadList.push_back(std::thread(factor, Ap, Ai, Ax, b, Q, P, Pinv, n, 30000, 35000));
  threadList.push_back(std::thread(factor, Ap, Ai, Ax, b, Q, P, Pinv, n, 35000, 40000));

// wait for all threads to finish
for (auto& threadID : threadList){
    threadID.join();
}

}

有没有办法在每次调用函数parallel_klu时避免创建8个线程？ 有点像为第一次调用创建它们然后只是发送一个信号让线程再次执行。

Answer 1

首先，我强烈建议弄清楚线程创建是否会破坏应用程序的性能。

如果是，您可以使用一个称为线程池的概念，它基本上是一组可以发送任务的线程，并且在没有任何操作时保持线程构建/活动。 此概念还可用于修复工作线程的数量。 这个答案给出了一些很好的建议。