jhipster身份验证使用电子邮件登录

Question

我正在寻找一种使用电子邮件 / 密码作为身份验证的方法，而不是默认的登录名（用户名）/ 密码 。

我正在使用spring security oauth2。

这可能吗？ 我允许为用户更改电子邮件。

谷歌不是我的朋友。

我的代码也没有黑客攻击：当在登录列中放入相同的电子邮件时，我收到了身份验证错误

Answer 1

在'com.example.myjhipster.security.UserDetailsS​​ervice'中找到（'mine'）解决方案

    @Override
    @Transactional
    public UserDetails loadUserByUsername(final String login) {
        log.debug("Authenticating {}", login);

        String lowercaseLogin = login.toLowerCase();
//        Optional<User> userFromDatabase =  userRepository.findOneByLogin(login);
        Optional<User> userFromDatabase =  userRepository.findOneByEmail(login);
        return userFromDatabase.map(user -> {
            if (!user.getVerified()) {
                throw new UserNotActivatedException("User " + lowercaseLogin + " was not activated");
            }

            List<GrantedAuthority> grantedAuthorities = user.getAuthorities().stream()
                    .map(authority -> new SimpleGrantedAuthority(authority.getName()))
                    .collect(Collectors.toList());
//            return new org.springframework.security.core.userdetails.User(lowercaseLogin,
            return new org.springframework.security.core.userdetails.User(user.getLogin(),
                    user.getPassword(),
                    grantedAuthorities);
        }).orElseThrow(() -> new UsernameNotFoundException("User " + lowercaseLogin + " was not found in the database"));
    }

Answer 2

这可能有点太晚了，但这里有一个能够理解登录和电子邮件的解决方案。

@Override
@Transactional
public UserDetails loadUserByUsername(final String login) {
    log.debug("Authenticating {}", login);
    String lowercaseLogin = login.toLowerCase(Locale.ENGLISH);

   User user = userRepository.findOneByLogin(lowercaseLogin)
           .map(Optional::of)
           .orElse(userRepository.findOneByEmail(lowercaseLogin))
           .orElseThrow(() -> new UsernameNotFoundException("User " + lowercaseLogin + " was not found in the " + "database"));

   if (!user.getActivated()) {
       throw new UserNotActivatedException("User " + lowercaseLogin + " was not activated");
   }

   List<GrantedAuthority> grantedAuthorities = getGrantedAuthorities(user);

   return new org.springframework.security.core.userdetails.User(user.getLogin(),
          user.getPassword(),
          grantedAuthorities);

}

private List<GrantedAuthority> getGrantedAuthorities(User user) {
    return user.getAuthorities().stream()
            .map(authority -> new SimpleGrantedAuthority(authority.getName()))
        .collect(Collectors.toList());
}