[英]Pass PHP variable to JavaScript thru the DOM works, but can't pass that same variable back from JS to PHP
[英]Can't pass variable from PHP to JS
我想用php代码从我的MySQL服务器加载数据,然后用它来绘制带有Google图表的图表。 问题是我无法在Java脚本代码中使用从mysql查询的数据。
PHP代码 :
$connection = mysql_connect('127.0.0.1','root','123456');
mysql_select_db('db_statmarket',$connection);
$result2 = mysql_query('select sum(`How much read from customer`) as Leads, Date from monitor group by Date;',$connection) or die('cannot show tables');
在javascript代码中,我们可以在其中看到var data = ...
我希望他将成为我从数据库中查询的表。
HTML和JS代码 :
<script type="text/javascript">
google.setOnLoadCallback(drawChart);
function drawChart() {
var data = google.visualization.arrayToDataTable([
['Year', 'Sales', 'Expenses'],
['2004', 1000, 400],
['2005', 1170, 460],
['2006', 660, 1120],
['2007', 1030, 540]
]);
var options = {
title: 'Company Performance',
curveType: 'function',
legend: { position: 'bottom' }
};
var chart = new google.visualization.LineChart(document.getElementById('curve_chart'));
chart.draw(data, options);
}
</script>
输出应如下所示:
像这样:
<?php
$connection = mysql_connect('127.0.0.1','root','123456');
mysql_select_db('db_statmarket',$connection);
$result2 = mysql_query('select sum(`How much read from customer`) as Leads, Date from monitor group by Date;',$connection) or die('cannot show tables');
$json = array();
while($row = mysql_fetch_assoc($result2)) {
$json[] = $row;
}
?>
<script type="text/javascript">
var data = <?php echo json_encode($json); ?>;
// chart code here
</script>
如果您的JavaScript位于.js文件中,则可以:
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