当计数需要数据从此select语句计算时，如何在mysql中按计数排序？

Question

看我的代码，在我从该选择语句中获取数据后，我希望按计数百分比选择一条语句，这显然是不合逻辑的。 我能做什么？ 帮助，感激不尽。

 <?php //myslq connection code, remove it because it's not relate to this question $stm =$db->prepare("SELECT id ,term_count, COUNT(user_id) as count FROM sign WHERE term IN (:term_0,:term_1) GROUP BY user_id ORDER by count DESC"); //trying replace order by count with $combine_count, but it's wrong $term_0="$term[0]"; $term_1="$term[1]"; $stm->bindParam(":term_0", $term_0); $stm->bindParam(":term_1", $term_1); stm->execute(); $rows = $stm->fetchALL(PDO::FETCH_ASSOC); foreach ($rows as rows) { $count=$rows['count']; $term_count_number=$rows['term_count']; $count_percentage=round(($count/$count_user_diff)*100); $count_key_match=round(($count/$term_count_number)*100); $combine_count=round(($count_percentage+$count_key_match)/2); //issue is here, I want the select statement order by $combine_count } ?> 

Answer 1

SELECT  id ,term_count, COUNT(user_id) as `count`
    FROM  sign
    WHERE  term IN (:term_0,:term_1)
    GROUP BY  user_id
    ORDER by  `count` DESC"); 

由于“计数”是一个函数，因此最好在非函数“计数”周围添加后缀，如上所述。

GROUP BY应该列出未聚合的字段。 否则，它不知道要获取哪个id和term_count。 因此，根据您的需求，

要么做

SELECT  user_id, COUNT(*) as `count`  -- I changed this line
    FROM  sign
    WHERE  term IN (:term_0,:term_1)
    GROUP BY  user_id
    ORDER by  `count` DESC"); 

或做

SELECT  id ,term_count, COUNT(*) as `count`
    FROM  sign
    WHERE  term IN (:term_0,:term_1)
    GROUP BY  id ,term_count    -- I changed this line
    ORDER by  `count` DESC"); 

Answer 2

SQL语法逻辑

SELECT column1, count(column1) AS amount
FROM table_name
GROUP BY column1
ORDER BY amount DESC
LIMIT 12