我可以将这两个SQL查询合并为一个吗？

Question

drink_orders有很多drink_order_extras

首先：

SELECT
  Sum(drink_orders.quantity * drink_orders.drink_price) AS drink_total
FROM
  drink_orders
WHERE
  drink_orders.reservation_id = 3610

第二个

SELECT
  Sum(drink_order_extras.quantity * drink_order_extras.drink_price) AS extra_total
FROM
  drink_order_extras INNER JOIN
  drink_orders ON drink_order_extras.drink_order_id = drink_orders.id
WHERE
  drink_orders.reservation_id = 3610

获得总计也很不错（drink_total + extra_total）

仅供参考，下面不会导致正确的总和：

SELECT
  Sum(drink_orders.quantity * drink_orders.drink_price) AS drink_total,
  Sum(drink_order_extras.quantity * drink_order_extras.drink_price) AS extra_total
FROM
  drink_order_extras INNER JOIN
  drink_orders ON drink_order_extras.drink_order_id = drink_orders.id
WHERE
  drink_orders.reservation_id = 3610

编辑：

Gordon Linoff的回答非常好：

SELECT Sum(do.quantity * do.drink_price) AS drink_total,
   Sum(extras_total) as extras_total,
   (Sum(do.quantity * do.drink_price) + COALESCE(Sum(extras_total), 0)
   ) as total
FROM drink_orders do LEFT JOIN
 (SELECT doe.drink_order_id,
         Sum(doe.quantity * doe.drink_price) as extras_total
  FROM drink_order_extras doe
  GROUP BY drink_order_id
 ) doe
 ON do.id = doe.drink_order_id
WHERE do.reservation_id = 3610;

Answer 1

你在两个不同的维度上进行求和。 join导致笛卡尔积 - 抛出总和。 您可以在加入之前通过聚合来解决此问题：

SELECT Sum(do.quantity * do.drink_price) AS drink_total,
       Sum(extras_total) as extras_total,
       (Sum(do.quantity * do.drink_price) + COALESCE(Sum(extras_total), 0)
       ) as total
FROM drink_orders do LEFT JOIN
     (SELECT doe.drink_order_id,
             Sum(doe.quantity * doe.drink_price) as extras_total
      FROM drink_orders_extras doe
      GROUP BY drink_order_id
     ) doe
     ON do.id = doe.drink_order_id
WHERE do.reservation_id = 3610;

这首先将额外费用计入饮品订单。 然后它将所有饮料订单信息汇总为预订级别。

Answer 2

尝试这个：

select sum(total) from (
SELECT
  Sum(drink_orders.quantity * drink_orders.drink_price) AS total
FROM
  drink_orders
WHERE
  drink_orders.reservation_id = 3610

UNION

SELECT
  Sum(drink_order_extras.quantity * drink_order_extras.drink_price) AS total
FROM
  drink_order_extras INNER JOIN
  drink_orders ON drink_order_extras.drink_order_id = drink_orders.id
WHERE
  drink_orders.reservation_id = 3610
) t