SUM的GROUP_CONCAT

Question

我有两个选择查询，都可以给出正确的结果：

SELECT SUM(value) AS "sum1" FROM table GROUP BY id1

和

SELECT SUM(value) AS "sum2" FROM table GROUP BY id1, id2

sum1是所有sum2项的总和，我想要一个查询，该查询为我提供sum1和所有sum2项的GROUP_CONCAT的结果。 但是，如何在sum2 -items元素的GROUP_CONCAT内定义GROUP BY？

SELECT SUM(value) AS "sum1", GROUP_CONACAT(SUM(value) AS "sum2" ... (?))
FROM table GROUP BY id1

Answer 1

您应该使用子查询来解决它，使用以下查询，我相信它将解决您的问题

select sum(t.part_sum) as sum1, group_concat(t.part_sum) as sum2 from (select sum(value) as part_sum from table group by id1, id2) as t