使用HTTP Post，Java，Json，PHP的Android注册表格

Question

我正在尝试将用户注册到我的Web托管SQL数据库中。 希望Java应用程序将这些值发布到Web上以进行格式化，然后再放入SQL语句中。

下面是我的代码来处理服务器上的POST请求。

$password=$_POST["password"]; 
$username=$_POST["username"]; 
$first = $_POST["first"];
$second = $_POST["second"];
$password = sha1($password);

$query = "INSERT INTO plateusers (email, password, first, second) 
      VALUES ('$username','$password', '$first', '$second')";

       if ($query_run = mysqli_query($mysqli_conn, $query)) {
                $response["success"] = 1;
                  $response["message"] = "You have been registered"; 
                  die(json_encode($response));
       } 
       else 
           { 
                $response["success"] = 0;
                $response["message"] = "Invalid details";
                die(json_encode($response));
           } 
           mysql_close(); 

首先，我知道我的声明可以接受，但是在声明生效后才能保证安全。

然后，我创建了一个表单供用户在RegisterActivity中输入其详细信息，其代码为：

public class RegisterActivity extends ActionBarActivity {

Context c;
EditText eTEmail;
EditText eTPassword;
EditText eTFname;
EditText eTSname;

ImageButton iBLogin;
String password;
String email;
String fname;
String sname;
String url = "*******";

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    c = this;

    setContentView(R.layout.activity_register);

    //Casting
    eTEmail = (EditText) findViewById(R.id.eTEmail);
    eTPassword = (EditText) findViewById(R.id.eTPassword);
    eTFname = (EditText) findViewById(R.id.eTFname);
    eTSname = (EditText) findViewById(R.id.eTSname);
    iBLogin = (ImageButton) findViewById(R.id.iBLogin);

    iBLogin.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View v) {
            //  _("Login button hit");

            email = eTEmail.getText() + "";
            fname = eTFname.getText() + "";
            sname = eTSname.getText() + "";
            password = eTPassword.getText() + "";

            if (sname.length() == 0 || fname.length() == 0 || email.length() == 0 || password.length() == 0) {
                Toast.makeText(c, "Please fill in all fields", Toast.LENGTH_SHORT).show();
                return;
            }

            if (sname.length() > 0 && fname.length() > 0 && email.length() > 0 && password.length() > 0) {
                //Do networking
                Networking n = new Networking();
                n.execute(url, Networking.NETWORK_STATE_REGISTER);
            }

        }
    });
}


//AsyncTask good for long running tasks
public class Networking extends AsyncTask {

    public static final int NETWORK_STATE_REGISTER = 1;

    @Override
    protected Object doInBackground(Object[] params) {

        getJson((String) params[0], (Integer) params[1]);
        return null;
    }
}

private void getJson(String url, int state) {
    //Do a HTTP POST, more secure than GET
    HttpClient httpClient = new DefaultHttpClient();
    HttpPost request = new HttpPost(url);
    List<NameValuePair> postParameters = new ArrayList<NameValuePair>();

    boolean valid = false;

    switch (state) {
        case Networking.NETWORK_STATE_REGISTER:
            //Building key value pairs to be accessed on web
            postParameters.add(new BasicNameValuePair("username", email));
            postParameters.add(new BasicNameValuePair("password", password));
            postParameters.add(new BasicNameValuePair("first", fname));
            postParameters.add(new BasicNameValuePair("second", sname));

            valid = true;


            break;
        default:
            // Toast.makeText(c, "Unknown state", Toast.LENGTH_SHORT).show();

    }

    if (valid == true) {
        //Reads everything that comes from server
        BufferedReader bufferedReader = null;
        StringBuffer stringBuffer = new StringBuffer("");
        try {
            UrlEncodedFormEntity entity = new UrlEncodedFormEntity(postParameters);
            request.setEntity(entity);

            //Send off to server
            HttpResponse response = httpClient.execute(request);

            //Reads response and gets content
            bufferedReader = new BufferedReader(new InputStreamReader(response.getEntity().getContent()));

            String line = "";
            String LineSeparator = System.getProperty("line.separator");
            //Read back server output
            while ((line = bufferedReader.readLine()) != null) {
                stringBuffer.append(line + LineSeparator);
            }

            bufferedReader.close();
        } catch (Exception e) {
            //Toast.makeText(c, "Error during networking", Toast.LENGTH_SHORT).show();
            e.printStackTrace();
        }

        decodeResultIntoJson(stringBuffer.toString());

        //Toast.makeText(c, "Valid details", Toast.LENGTH_SHORT).show();
    } else {
        //Toast.makeText(c, "Invalid details", Toast.LENGTH_SHORT).show();

    }
}

private void decodeResultIntoJson(String response) {
    /* Example from server
    {
       "success":1,
       "message":"You have been successfully registered"
    }
     */
    if (response.contains("error")) {
        try {
            JSONObject jo = new JSONObject(response);
            String error = jo.getString("error");
        } catch (JSONException e) {
            e.printStackTrace();
        }
    }

    try {
        JSONObject jo = new JSONObject(response);

        String success = jo.getString("success");
        String message = jo.getString("message");
       // Toast.makeText(c, "Register successful", Toast.LENGTH_SHORT).show();


    } catch (JSONException e) {
        e.printStackTrace();
    }
}
}

这是我首次尝试开发Android应用程序，感谢您的任何帮助。

由于明显的原因， Url变量已被注释掉，它链接到上述php脚本。

运行时似乎没有数据库添加，但是仅运行脚本将允许输入数据库，我认为发布数据存在问题

Answer 1

确保我的应用程序可以连接到互联网解决了该问题。 直到找到合适的代码来解决该问题，我才知道这个问题。

    <uses-permission android:name="android.permission.INTERNET" />
    <uses-permission android:name="android.permission.ACCESS_NETWORK_STATE" />