[英]Stringifying a Java Object throwing Error in JSON.parse Javascript
我定义了一个具有以下详细信息的类电子邮件:
Email
:
String name;
String subject;
List<String> attachment;
String jsonContent;
....
在上面的类中, jsonContent
变量加载了经过分层处理的json对象。
创建电子邮件对象后,我将对整个电子邮件对象进行字符串化并发送给客户端。
我需要在客户端中解析电子邮件对象并在UI中呈现它。
但是它会为客户端中的电子邮件对象引发解析错误,即
JSON.parse(emailString);
因为jsonContent
字段内有双引号。
这是对具有已字符串化的jsonContent
变量的JAVA对象进行字符串化的问题。
修复它的一种方法是将jsonContent
变量定义为对象而不是String。 还有其他解决方法吗?
电子邮件JSON示例:
{
"id": "e4682ec0-a7c3-4f4d-abcd-f404f5fdb1eb",
"entityType": "email",
"subject": "Presentation 1",
"from": "aaa <a@a.com>",
"to": [
"undisclosed-recipients:;"
],
"cc": [],
"bcc": [
"jack.porter@forwardaccelerator.com"
],
"recievedDate": 1423101398000,
"recievedDateString": "Wed, 4 Feb 2015 12:26:38 -0800",
"bodyText": " Please find the link to my recent presentation",
"jsonContent": "{
"typeOfMail": "NormalMail",
"normalMail": {
"mailType": "NormalMail",
"paragraphs": [
"Pleasefindthelinktomyrecentpresentation"
]
}
}"
}
您将需要转义许多字符串才能将东西作为字符串获取。
要将json对象存储在json对象中,您需要对其进行转义。 所以
"jsonContent": "{
"typeOfMail": "NormalMail",
"normalMail": {
"mailType": "NormalMail",
"paragraphs": [
"Pleasefindthelinktomyrecentpresentation"
]
}
}"
变
"jsonContent": "{\\"typeOfMail\\": \\"NormalMail\\",\\"normalMail\\":{\\"mailType\\":\\"NormalMail\\",\\"paragraphs\\":[\\"Pleasefindthelinktomyrecentpresentation\\"]}}"
现在,如果要在Java中进行编译,这就是您将其手动输入为Java字符串(执行代码段)时的样子。
var json = { "id": "e4682ec0-a7c3-4f4d-abcd-f404f5fdb1eb", "entityType": "email", "subject": "Presentation 1", "from": "aaa <a@a.com>", "to": [ "undisclosed-recipients:;" ], "cc": [], "bcc": [ "jack.porter@forwardaccelerator.com" ], "recievedDate": 1423101398000, "recievedDateString": "Wed, 4 Feb 2015 12:26:38 -0800", "bodyText": " Please find the link to my recent presentation", "jsonContent": "{\\"typeOfMail\\": \\"NormalMail\\",\\"normalMail\\":{\\"mailType\\":\\"NormalMail\\",\\"paragraphs\\":[\\"Pleasefindthelinktomyrecentpresentation\\"]}}" } console.log("This is the json object having a string with json"); console.log(json); console.log("This is it parsed as string"); var x = {hello:JSON.stringify(json)}; console.log(JSON.stringify(x).substring(10,JSON.stringify(x).length-2)); document.getElementById('content').textContent = JSON.stringify(x).substring(10,JSON.stringify(x).length-2);
<div id="content"></div>
这就是发送的JSON文件/请求答案中的样子
{
"id": "e4682ec0-a7c3-4f4d-abcd-f404f5fdb1eb",
"entityType": "email",
"subject": "Presentation 1",
"from": "aaa <a@a.com>",
"to": [
"undisclosed-recipients:;"
],
"cc": [],
"bcc": [
"jack.porter@forwardaccelerator.com"
],
"recievedDate": 1423101398000,
"recievedDateString": "Wed, 4 Feb 2015 12:26:38 -0800",
"bodyText": " Please find the link to my recent presentation",
"jsonContent": "{\"typeOfMail\": \"NormalMail\",\"normalMail\":{\"mailType\":\"NormalMail\",\"paragraphs\":[\"Pleasefindthelinktomyrecentpresentation\"]}}"
}
现在我不明白为什么要使用JSONContent作为字符串,因为您可以将其作为对象传递(去掉它周围的引号,这样您就可以
"jsonContent": {
"typeOfMail": "NormalMail",
"normalMail": {
"mailType": "NormalMail",
"paragraphs": [
"Pleasefindthelinktomyrecentpresentation"
]
}
}
如果您需要它作为javascript中的字符串,则可以执行JSON.stringify(json.jsonContent);
为了更容易获得相同的结果。
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