从UINavigationController展开到UIViewController

Question

我有一个MYViewController ，它使用自定义segue预设了MYNavigationController

- (void)perform
{
    [self.sourceViewController presentViewController:self.destinationViewController animated:NO completion:nil];
}

我也放松一下，就像

- (void)perform
{
    [self.sourceViewController dismissViewControllerAnimated:NO completion:nil];
}

在情节MYNavigationController ， MYNavigationController和Navigation Controller Scene中的Exit占位符之间存在连接-标识为unwindToVC1的展开unwindToVC1 。

MYNavigationController看起来像这样

...

- (UIStoryboardSegue *)segueForUnwindingToViewController:(UIViewController *)toViewController fromViewController:(UIViewController *)fromViewController identifier:(NSString *)identifier 
{
    MYCustomUnwindSegue *segue = [[MYCustomUnwindSegue alloc] initWithIdentifier:identifier source:fromViewController destination:toViewController];

    return segue;
}

- (IBAction)unwindToVC1:(UIStoryboardSegue *)sender
{
}

- (IBAction)dissmissMYNavigationController:(id)sender
{
    [self performSegueWithIdentifier:@"unwindToVC1" sender:sender];
}

...

因此，当我调用-dissmissMYNavigationController没有任何反应。 甚至-segueForUnwindingToViewController:fromViewController:identifier:也不会被调用。

我究竟做错了什么？ 谢谢！

Answer 1

如果要从导航器控制器中删除顶部ViewController，则必须调用popViewControllerAnimated: 当您呈现模式ViewController时，将使用dismissViewControllerAnimated 。

Answer 2

似乎我不清楚如何放松，所以

- (UIStoryboardSegue *)segueForUnwindingToViewController:(UIViewController *)toViewController fromViewController:(UIViewController *)fromViewController identifier:(NSString *)identifier 
{
    MYCustomUnwindSegue *segue = [[MYCustomUnwindSegue alloc] initWithIdentifier:identifier source:fromViewController destination:toViewController];

    return segue;
}

- (IBAction)unwindToVC1:(UIStoryboardSegue *)sender
{
}

应该在MYViewController ，而不在MYNavigationController