从数组中获取特定值

Question

我有一个来自这段代码的数组

echo "<pre>";
print_r($_SESSION["followers"]);
echo "</pre>";

数组是

Array
(
    [pagination] => Array
        (
        )

    [meta] => Array
        (
            [code] => 200
        )

    [data] => Array
        (
            [0] => Array
                (
                    [username] => SD
                    [profile_picture] => https://instagramimages-a.akamaihd.net/profiles/profile_4.jpg
                    [id] => 42114932
                    [full_name] => A
                )

            [1] => Array
                (
                    [username] => ER
                    [profile_picture] => https://igcdn-photos-c-a.akamaihd.net/hphotos-ak-xpf1/t51.2885-19/1.jpg
                    [id] => 395834289
                    [full_name] => P
                )

        )

)

我想知道是否有可能匹配数组中的特定值，然后获取与其相关的其他值，

例如，我正在获得id = 42114932的值，现在我希望在给定数组中匹配此值以及它匹配的任何地方，我希望获取该id的用户名，全名和个人资料照片，在这种情况下对应于id 42114932我希望要得到

username=SD, 
full_nmae=A
profile_pic = https://instagramimages-a.akamaihd.net/profiles/profile_4.jpg

如果有可能，任何人都可以告诉它是如何做到的

Answer 1

一个选项是循环通过数组

$f = ..;  //(the id to find)
for($i = 0, $i < count($data); i++)
{
    if($data[$i]['id'] == $f){
        echo 'Full name : '.$data[$i]['fullname'];
        echo '<br />Username : '.$data[$i]['username'];
        echo '<br />Profile picture : '.$data[$i]['profile_pic'];
    }
}

我觉得这可行吗？ 可能想要调整for循环的计数器。

Answer 2

此代码可能对您有所帮助：

  $arr = $_SESSION["followers"]['data'];
    $id = 42114932;
    $count = count($arr);
    $foundArr = array();
    for ($i = 0; $i< $count; $i++) {
       if ($arr['id'] == $id) {
         $foundArr[$i] = $arr[$i];
         break;
       }
    }
    print_r($foundArr)

Answer 3

以下守则是不言自明的：

<?php
$_SESSION["followers"];

echo "<pre>";
print_r($_SESSION["followers"]);
echo "</pre>";



$yourID = 42114932;
for($x=0;$x<(count($_SESSION["followers"]['data']));$x++){
    if($yourID  == $_SESSION["followers"]['data'][$x]['id']){ //compare your id to each record
        echo "Full name : ".$array['data'][$x]['full_name'];
        echo "<br>Username : ".$array['data'][$x]['username'];
        echo "<br>Profile picture : ".$array['data'][$x]['profile_picture'];
        echo "<br>";
    }
}

Answer 4

function getMetaInfo(array $array, $id, $arrayBranch = NULL){ 
    if($arrayBranch === NULL){
        return FALSE;
    }

    $returnArray = array();

    foreach($array[$arrayBranch] as $key => $value){
         if($value['id'] == $id){
              unset($value['id']);
              $returnArray[$id] = $value;
              return $returnArray;
         }
    }

}

Answer 5

你可以尝试这样的事情：

 $row = fetchData($_SESSION["followers"]['data'], 'id', 42114932); // Here you will get the comlet row of data you are searching

function fetchData($data, $column, $value){
    for($i = 0, $i < count($data), i++)
    {
        if($data[$i][$column] == $value){
            return $data[$i]; // returns a complete row.
        }
    }
}