[英]Getting all children in a LinearLayout
如何让所有孩子以后使用它们?
LinearLayout createRow(LinearLayout parrent, int id, int orientation, int color){
LinearLayout cell = new LinearLayout(this);
LinearLayout.LayoutParams rowParams = new LinearLayout.LayoutParams(
LinearLayout.LayoutParams.MATCH_PARENT,
LinearLayout.LayoutParams.MATCH_PARENT);
rowParams.weight = 1;
rowParams.setMargins(5,2,5,2);
cell.setLayoutParams(rowParams);
cell.setBackgroundColor(color);
cell.setOrientation(orientation);
cell.setId(id);
parrent.addView(cell);
cell.setOnClickListener(cellListener);
return cell;
}
您可以使用getChildCount()
获得布局getChildCount()
的数量,一旦拥有,就可以像这样循环遍历它们:
int childCount = cell.getChildCount();
View child;
for(int i=0; i++; i<childCount)
{
child = cell.getChildAt(i);
// do what you want with each child element
}
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.